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Xelga [282]
3 years ago
10

Find the probability of at least 2 girls in births. Assume that male and female births are equally likely and that the births ar

e independent events. Round to three decimal places.
Mathematics
1 answer:
tiny-mole [99]3 years ago
6 0
We assume that male and female births are equally likely, it means that the probability of birth of male= probability of birth of female = 100%/2=50% or 0.5We have 2 independent events. So what will be the variants:
Male and FemaleMale  and Male Female and Male Female and Female 
All four variants are equally likely.Probability of each one is 1/4 = 0.25.So, Result "Female and Female"
 are probability = 0.250 --- if round to three decimal places.
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Answer:

725 Boxes of Popcorn

Step-by-step explanation:

You can do it simply by just typing in the calculator 4893.75÷6.75.

But I can show my work. Picture below

5 0
2 years ago
Which expressions are equivalent to 12x - 6? ​
iren2701 [21]
<h3>Answer</h3>

B and E

<h3>Explanation</h3>

A) It's wrong because

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B) It's right because

6 \times (2x - 1) = 12x - 6

C) It's wrong because

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D) It's wrong because

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E) It's right because

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F) It's wrong because

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8 0
3 years ago
What is the reminder when (3x^3-2x^2+4x-3) is divided by (x^2+3x+3)
NARA [144]
(For full answer you might have to go to the comments)

Answer: 28x+30

Explanation: we divide (3x^3-2x^2+4x-3) by (x^2+3x+3) Using long division
3x-11
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(x^2+3x+3) 3x^3-2x^2+4x-3


-(3x^3+9x^2+9x)
__________________

-11x^2-5x-3

-(-11x^2-33x-33)
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So our remainder will be 28x+30
5 0
3 years ago
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lara [203]

Answer:

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Step-by-step explanation:

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but this might be wrong

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s

Step-by-step explanation:

3 0
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