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iren2701 [21]
3 years ago
8

At Best Burgers, Jack collected sales data on the type of side order served with each type of burger purchased for a week. Jack

serves a half pound of onion rings with every kind of burger. If Jack sells 120 bacon cheeseburgers total, about how many pounds of onion rings will he serve with them? (round to nearest whole number)At a mall food court, the first 40 orders for the day are given below. • 22 pizza slices • 8 hamburgers • 4 hot dogs • 6 fried chicken Based on this information, how many hamburger orders could be expected from 300 customers?
Mathematics
2 answers:
horsena [70]3 years ago
4 0

The <em><u>correct answers</u></em> are:

60 pounds of onion rings and 60 hamburgers.

Explanation:

Jack serves a half pound of onion rings with every burger.  He serves 120 bacon cheeseburgers.  To find the number of pounds of onion rings, we multiply 1/2 pound by 120 burgers:

1/2(120) = 1/2(120/1) = (1*120)/(2*1) = 120/2 = 60 pounds of onion rings.

There were 8 hamburgers served out of the first 40 orders.  If this rate continues, then to find the number of hamburgers out of 300 orders, we multiply 8/40 by 300:

8/40(300) = 8/40(300/1) = (8*300)/(40*1) = 2400/40 = 60

There would be 60 hamburgers.

Andreyy893 years ago
4 0

Question:   <em><u>At Best Burgers, Jack collected sales data on the type of side order served with each type of burger purchased for a week.  </u></em>

<em><u> Jack serves a half pound of onion rings with every kind of burger.  </u></em>

<em><u> If Jack sells 120 bacon cheeseburgers total, about how many pounds of onion rings will he serve with them? (round to nearest whole number)</u></em>

<h2>Answer:    The answer is C) 30 pounds</h2><h2></h2>

Step by step explanation:

Bacon cheeseburger with onion rings:  

\frac{40}{(41 + 40)} = \frac{40}{81} = 0.4938

after that,  120 x 0.4938 = 59.256

then,  59.256 x .50 = 29.628

So 29.628 rounded is 30 and that is C

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Graphing the complex number we see the angle terminates in the second quadrant. This means the argument, the angle, will be between 90 degrees and 180 degrees.

So if we create a right triangle with that point after graphing it. We see the height of that triangle is 5 because that is the imaginary part. The base of that triangle has length 5\sqrt{3}. The problem is this doesn't give us any part of the angle we want, but it does give us the complementary of the part of the angle that is in second quadrant.

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