1) B irrational
2) B sometimes because a negative integer is not a whole number
3) C irrationals
4) C and D are whole numbers
5) C irrational
6) D 7/10 because a rational number is always a faction
7) C rational numbers
8) D real and rational
9) D rational, real, whole number
10) A integers
In this problem, we need to plug in the given x values for
![f(x)=0](https://tex.z-dn.net/?f=%20f%28x%29%3D0%20)
and find a and b.
When we plug in 1, we get:
![2 \times {1}^{4} - 5 \times {1}^{3} - 14 \times {1}^{2} + a \times 1 + b = 0](https://tex.z-dn.net/?f=2%20%5Ctimes%20%7B1%7D%5E%7B4%7D%20-%205%20%5Ctimes%20%7B1%7D%5E%7B3%7D%20-%2014%20%5Ctimes%20%7B1%7D%5E%7B2%7D%20%2B%20a%20%5Ctimes%201%20%2B%20b%20%3D%200)
Simplify:
![2 - 5 - 14 + a + b = 0](https://tex.z-dn.net/?f=2%20-%205%20-%2014%20%2B%20a%20%2B%20b%20%3D%200)
![- 17 + a + b = 0](https://tex.z-dn.net/?f=%20-%2017%20%2B%20a%20%2B%20b%20%3D%200)
![a + b = 17](https://tex.z-dn.net/?f=a%20%2B%20b%20%3D%2017)
We got our first statement about the values of the variables. If we find one more we can find those 2 variables.
We have another given root: 4.
Plug it in:
![2 \times {4}^{4} - 5 \times {4}^{3} - 14 \times {4}^{2} + a \times 4 + b = 0](https://tex.z-dn.net/?f=2%20%5Ctimes%20%7B4%7D%5E%7B4%7D%20-%205%20%5Ctimes%20%7B4%7D%5E%7B3%7D%20-%2014%20%5Ctimes%20%7B4%7D%5E%7B2%7D%20%2B%20a%20%5Ctimes%204%20%2B%20b%20%3D%200)
![512 - 320 - 224 + 4a + b = 0](https://tex.z-dn.net/?f=512%20-%20320%20-%20224%20%2B%204a%20%2B%20b%20%3D%200)
![- 32 + 4a + b = 0](https://tex.z-dn.net/?f=%20-%2032%20%2B%204a%20%2B%20b%20%3D%200)
![4a + b = 32](https://tex.z-dn.net/?f=4a%20%2B%20b%20%3D%2032)
Now we have our second one. We can combine them:
![a + b = 17 \\ 4a + b = 32](https://tex.z-dn.net/?f=a%20%2B%20b%20%3D%2017%20%5C%5C%204a%20%2B%20b%20%3D%2032)
I use elimination method which is easier here.
Multiply the top equation by -1:
![- a - b = - 17 \\ 4a + b = 32](https://tex.z-dn.net/?f=%20-%20a%20-%20b%20%3D%20-%2017%20%5C%5C%204a%20%2B%20b%20%3D%2032)
Add them up:
![3a = 15](https://tex.z-dn.net/?f=3a%20%3D%2015)
Simplify:
![a = 5](https://tex.z-dn.net/?f=a%20%3D%205)
Now we have a, we can plug in one of those equations to find b:
![5 + b = 17](https://tex.z-dn.net/?f=5%20%2B%20b%20%3D%2017)
![b = 17 - 5](https://tex.z-dn.net/?f=b%20%3D%2017%20-%205)
![b = 12](https://tex.z-dn.net/?f=b%20%3D%2012)
So, the answers are
![a=5](https://tex.z-dn.net/?f=a%3D5)
and
![b=12](https://tex.z-dn.net/?f=b%3D12)
.
Answer:
The value of x is 25
Step-by-step explanation:
x² when x = 5
So,
(5)² = 5 × 5 = 25
Thus, The value of x is 25
<u>-TheUnknownScientist</u><u> 72</u>
Answer:
Assignment: 01.07 Laboratory TechniquesAssignment: 01.07 Laboratory Techniques
Step-by-step explanation:
Assignment: 01.07 LaboratoryAssignment: 01.07 Laboratory Techniques TechniquesAssignment: 01.07 Laboratory TechniquesAssignment: 01.07 Laboratory Techniques