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MaRussiya [10]
3 years ago
15

10 POINTS! HELP ITS DUE SOON!!

Mathematics
1 answer:
Naddika [18.5K]3 years ago
8 0

Answer:

10

Σ [n^2]

i=1

Step-by-step explanation:

Hope I helped? I inserted it into a calc and I also got 385 for something if its useful))

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I will give you brainliest whoever answers correct first!!
nikklg [1K]

Answer:

X = 24

Step-by-step explanation:

180 - 156 = 24

These are supplementary and equal to 180.

7 0
3 years ago
Suppose that are Yi.....Yn are i.i.d random variables with a Nâ(âμY, Ï^2Y â) distribution. How would the probability density of
svp [43]

Answer:

b. As the sample size â increases, the variance of decreases. â So, the distribution of becomes highly concentrated around.

Step-by-step explanation:

Let : Yi,.... Yn are = i.i.d are random variables. The probability density of the distribution varies along with the sample size. When the sample size changes, the probability density of $E^3$ also changes.

The probability distribution may be defined as the statistical expression which defines the likelihood of any outcome for the discrete random variable and it can be opposed to the continuous random variable.

In the context, when the size of the sample of the distribution size increases, it causes a decrease in the variance and so the distribution becomes highly concentrated around.

5 0
3 years ago
Each bacterium in a petri dish splits into 2 bacteria after one day. The function b(d) = 600 • 24 models
TiliK225 [7]

Answer:

(a)Initial Number of Bacteria=600

(b)\text{Number of bacteria after 5 days}=19200

Step-by-step explanation:

Given an initial number  b_0 of bacteria in a petri dish, and each bacteria splits into 2 bacteria after one day.

The function b(d) = 600 \cdot 2^d models  the number of bacteria, b after d days.

<u>Part A</u>

Given  b(d) = 600 \cdot 2^d

When d=0,

The initial number of bacteria in the petri dish,

b_0=b(0) = 600 \cdot 2^0=600

<u>Part B</u>

After 5 days, when d=5

b(5) = 600 \cdot 2^5=600 \cdot 32\\\text{Number of bacteria after 5 days}=19200

5 0
4 years ago
Mited
Natasha_Volkova [10]

9514 1404 393

Answer:

  • relative minimum -6√3 at x = -√3
  • relative maximum 6√3 at x = √3
  • decreasing on x < -√3 and x > √3
  • increasing on -√3 < x < √3
  • see below for a graph

Step-by-step explanation:

I find it convenient to draw the graph first when looking for relative extrema.

The function can be differentiated to get ...

  f'(x) = -3x^2 +9

This is zero when ...

  -3x^2 +9 = 0

  x^2 = 3

  x = ±√3 . . . . . x-values of relative extrema

Then the extreme values are ...

  f(±√3) = x(9 -x^2) = (±√3)(9 -3) = ±6√3

The lower extreme (minimum) corresponds to the lower value of x (-√3), so the extrema are ...

 (x, y) = (-√3, -6√3) and (√3, 6√3)

__

Since the leading coefficient is negative and the degree is odd, the function is decreasing for values of x below the minimum and above the maximum. It is increasing for values of  x between the minimum and the maximum.

  decreasing: x < -√3, and √3 < x

  increasing: -√3 < x < √3

7 0
3 years ago
My last points to ask a question pls show work
BartSMP [9]

Answer:

-9.5

Step-by-step explanation:

8.4×3=25.2

negative25.2- 5.7 equals negative 19.5 - 10. hey hi if my answer doesn't match with the answer in your book could you please tell me right away so that I can try another method or ask for help I would really like to help you bye.

6 0
3 years ago
Read 2 more answers
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