I believe -4 hope this helped
Green Line:
This is a horizontal line at x = 0, so it would be:
x ? 0
Since the shaded area is going to the left of 0 (this means x is negative):
x ≤ 0
Blue Line:
The shaded area is below the line, so:
y ≤ mx + b
When x = 0, y is -5.
y ≤ mx - 5
From each point, you go up 3 units, and to the right 4 units, so the slope is 
.
Answer:
A) 26
E) 12
Step-by-step explanation:
11x ≥ 132
x ≥ 12
The solution set would include numbers greater than or equal to 12
Answer:
Part A: a) Corresponding angles
Part B: b) 12x - 10 = 10x + 8
Part C: x = 9
m<1 = 98
m<2 = 82
Explanation:
B)
Since they're corresponding angles, they're equal to each other:
12x - 10 = 10x + 8
C)
12x - 10 = 10x + 8
2x = 18
x = 9
m<1:
12(9) - 10 = 98
m<2:
98 + y = 180
y = 82
<span>Let's find out the ball's acceleration
V^2 = U^2 + 2as
Where the distance S = 6 feet and U = 45.
Suppose he just took off so V = 0 and we are left with U^2 =2as
(45)^2 = 2a(6)
a = 2025/12 = 168.75 ft/s^2
Also S = ut + 1/2 at^2
Here S = 5ft and U= 0; a = 168.75. So we have 5 = (1/2) * 168.75 * t^2
So we have 5 * 2 = 168.75 t^2
T^2 = âš 10/ 168.75 = 0.00596 = âš0.006
T = 0.0077s</span>
