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vova2212 [387]
3 years ago
5

How do I put 2.625 into a fraction

Mathematics
2 answers:
Luba_88 [7]3 years ago
5 0
2 and 625/1000 (simp)  
<span>
 2 5/8 as a mixed number

25/8 as a regular fraction</span>
Ivenika [448]3 years ago
5 0
2 and 5/8

2 5/8 mixed number

21/8 as an improper fraction
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The Salk polio vaccine experiment in 1954 focused on the effectiveness of the vaccine in combating paralytic polio. Because it w
sdas [7]

Answer:

Step-by-step explanation:

Hello!

The variables of interest are:

X₁: Number of cases of polio observed in kids that received the placebo vaccine.

n₁= 201299 total children studied

x₁= 110 cases observed

X₂: Number of cases of polio observed in kids that received the experimental vaccine.

n₂= 200745 total children studied

x₂= 33 cases observed

These two variables have a binomial distribution. The parameters of interest, the ones to compare, are the population proportions: p₁ vs p₂

You have to test if the population proportions of children who contracted polio in both groups are different: p₂ ≠ p₁

a)

H₀: p₂ = p₁

H₁: p₂ ≠ p₁

α: 0.05

Z= \frac{(p'_2-p'_1)-(p_2-p_1)}{\sqrt{p'[\frac{1}{n_1} +\frac{1}{n_2} ]} }

Sample proportion placebo p'₁= x₁/n₁= 110/201299= 0.0005

Sample proportion vaccine p'₂= x₂/n₂= 33/200745= 0.0002

Pooled sample proportion p'= (x₁+x₂)/(n₁+n₂)= (110+33)/(201299+200745)= 0.0004

Z_{H_0}= \frac{(0.0002-0.0005)-0}{\sqrt{0.0004[\frac{1}{201299} +\frac{1}{200745} ]} }= -4.76

This test is two-tailed, using the critical value approach, you have to determine two critical values:

Z_{\alpha/2}= Z_{0.025}= -1.96

Z_{1-\alpha /2}= Z_{0.975}= 1.96

Then if Z_{H_0} ≤ -1.96 or if Z_{H_0} ≥ 1.96, the decision is to reject the null hypothesis.

If -1.96 < Z_{H_0} < 1.96, the decision is to not reject the null hypothesis.

⇒ Z_{H_0}= -4.76, the decision is to reject the null hypothesis.

b)

H₀: p₂ = p₁

H₁: p₂ ≠ p₁

α: 0.01

Z= \frac{(p'_2-p'_1)-(p_2-p_1)}{\sqrt{p'[\frac{1}{n_1} +\frac{1}{n_2} ]} }

The value of Z_{H_0}= -4.76 doesn't change, since we are working with the same samples.

The only thing that changes alongside with the level of significance is the rejection region:

Z_{\alpha /2}= Z_{0.005}= -2.576

Z_{1-\alpha /2}= Z_{0.995}= 2.576

Then if Z_{H_0} ≤ -2.576or if Z_{H_0} ≥ 2.576, the decision is to reject the null hypothesis.

If -2.576< Z_{H_0} < 2.576, the decision is to not reject the null hypothesis.

⇒ Z_{H_0}= -4.76, the decision is to reject the null hypothesis.

c)

Remember the level of significance (probability of committing type I error) is the probability of rejecting a true null hypothesis. This means that the smaller this value is, the fewer chances you have of discarding the true null hypothesis. But as you know, you cannot just reduce this value to zero because, the smaller α is, the bigger β (probability of committing type II error) becomes.

Rejecting the null hypothesis using different values of α means that there is a high chance that you reached a correct decision (rejecting a false null hypothesis)

I hope this helps!

8 0
4 years ago
The bait shop sells boxes of worms for fishing. The shop has 7 boxes left. There are 13 worms in each box.
worty [1.4K]
91 worms. 7 boxes multiplied by 13 worms per box equals 91 worms left in the shop
8 0
4 years ago
Draw a tend line on the scatter plot and name two points that your trend line passes through.​
Hatshy [7]

Answer:

ohifewdsviehdsids

Step-by-step explanation:

OEHWINDSHEDSIH

7 0
3 years ago
I NEED THIS FAST! I WILL PUT BRAINIEST IF IT IS CORRECT A group of workers is harvesting berries at a constant rate. An equation
Strike441 [17]
A) the slope of the equation is 5, the y intercept is 10. 
b) the rate of change is just the slope, so 5 but it means that they are picking 5 berries over that period of time. the initial amount is just the y intercept which is 10. this is just how many berries you start with.
c)

4 0
3 years ago
Can you help me ? I think I figured it out but am not sure . Thank you !
Nataly [62]

Thank you for posting the figure. Without it, I would have thought the parabola has a vertical axis.

For a parabola with a horizontal axis (as in this case), the equation of the parabola is

f(y)=a(y-k)^2+h

where (h,k) is the vertex.

Substituting (h,k)=(2,-4),

f(y)=a(y+4)^2+2...................(1)

as the equation of the parabola, with the value of "a" yet unknown.

Since we are given that the parabola passes through the point (-3,-3), we can substitute the corresponding x,y values in (1) to solve for a.

f(y)=-3=a(-3+4)^2+2

solve for a

a=(-3-2)/(1^2)=-5

So the equation of the parabola is f(y)=-5(y+4)^2+2

5 0
3 years ago
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