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natka813 [3]
3 years ago
6

Carnegie Learning, Inc

Mathematics
1 answer:
Vlad [161]3 years ago
4 0

Answer:

The expression of the pattern is n² + 2

Step-by-step explanation:

* Lets explain how to solve the problem

- Charlie starts with 3 guppy fish in his tank

- After one month he finds 6 guppy fish in his tank

- The following month, he finds 11 guppy fish in his tank

∵ The increasing in the next month is ⇒ 6 - 3 = 3

∵ The increasing in the following month is ⇒ 11 - 6 = 5

- The number is increasing by the consecutive odd numbers

∴ The nth rule is quadratic ⇒ an² + bn + c, where

   a + b + c = 1st term

   3a - b = the first difference

   2a = the constant difference between each two difference

∵ The first term is 3

∴ a + b + c = 3

∵ The first difference is 6 - 3 = 3

∴ 3a - b = 3

∵ 6 - 3 = 3 and 11 - 6 = 5

∵ 5 - 3 = 2

∴ The constant difference is 2

∴ 2a = 2 ⇒ divide both sides by 2

∴ a = 1

∵ 3a - b = 3

∴ 3(1) - b = 3

∴ 3 - b = 3 ⇒ subtract 3 from both sides

∴ b = 0

∵ a + b + c = 3

∴ 1 + 0 + c = 3

∴ 1 + c = 3 ⇒ subtract 1 from both sides

∴ c = 2

∵ The nth rule is ⇒ an² + bn + c , where n is the position of the number

∴ The nth rule = (1)n² + (0)n + 2

∴ The nth rule = n² + 2

∴ The expression of the pattern is n² + 2

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An artificial lake is in the shape of a rectangle and has an area of 9/20 square mile the width of the lake is 1/5 the length of
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Answer:  The dimensions are:   " 1.5 mi.  ×  ³⁄₁₀  mi. " .
_______________________________________________
             { length = 1.5 mi. ;  width =  ³⁄₁₀  mi. } .
________________________________________________
Explanation:
___________________________________________
Area of a rectangle:

A = L * w ; 

in which:  A = Area = (9/20) mi.² ,
                L = Length = ?
                w = width = (1/5)*L = (L/5) = ?
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  A = L * w ;  we want to find the dimensions; that is, the values for
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Plug in our given values:
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 (9/20) mi.² = L * (L/5) ;  in which: "w = L/5" ; 
 
     → (9/20) = (L/1) * (L/5) = (L*L)/(1*5) = L² / 5 ;
   
          ↔  L² / 5  = 9/20 ;
 
            →  (L² * ? / 5 * ?) = 9/20 ?    

                →     20÷5 = 4 ;  so; L² *4 = 9 ;
 
                   ↔    4 L² = 9 ; 
 
                   →  Divide EACH side of the equation by "4" ;
           
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______________________________________
           to get:  →  L² = 9/4 ; 
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     →   ⁺√(L²)   =   ⁺√(9/4) ;

    →   L  =  (√9) / (√4) ; 

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Let us check our answers:
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(3/2 mi.) * (3/10 mi.) =? (9/20) mi.² ??

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______________________________________________________
So the dimensions are: 

Length = (3/2) mi. ;  write as: 1.5 mi.

width = ³⁄₁₀ mi.
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or; write as:  " 1.5 mi.  ×  ³⁄₁₀ mi. " .
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