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3 years ago

All the Factors of x cubed minus 6x squared plus 11 minus 6

Mathematics

1 answer:

lutik1710 [3]3 years ago

8 0

Answer:

Step-by-step explanation:

f(x) = x^3 - 6x^2 + 11x - 6

By the Rational Roots theorem, the roots will be among ±1,2,3,6

So try the low-hanging fruit first. It is clear that f(1) = 0. So, factoring that out, you have

f(x) = (x-1)(x^2-5x+6)

Now factor the quadratic in the usual way.

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What value is added to both sides of the equation x2 − 2x = 10 in order to solve by completing the square?

VLD [36.1K]

Hi,
Answer C

$x^2-2x=10\\
x^2-2x+1=10+1\\

\Rightarrow\ (x-1)^2=11\\
\Rightarrow\ (x-1)^2-11=0\\
\Rightarrow\ (x-1)^2-( \sqrt{11})^2=0\\
\Rightarrow\ ((x-1)+ \sqrt{11})((x-1)- \sqrt{11})=0\\
\Rightarrow\ x-1+ \sqrt{11}=0\ or\ x-1- \sqrt{11}=0\\

\Rightarrow\ x=1- \sqrt{11}\ or\ x=1+ \sqrt{11}\\



$

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3 years ago

The domain is an interval. The domain is the function is (answer.)

Dmitriy789 [7]

Answer:

Domain :Set of all real values

Range : -5

Step-by-step explanation:

Here we see the blue line. Assuming it to be the graph of the function we are about to find Domain for.

Here we see that the graph is a straight line , parallel to x axis at y=-5

Hence the function will be

f(x)=-5

Also for every values of x, y =-5. Hence it is defined for all values of x. So the Domain is Set of All Real numbers

However,

For every value of x, the value of y is constant that is -5. Hence The range of f(x)=-5 is {-5}

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3 years ago

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Sindrei [870]

Answer:

x=40°

Step-by-step explanation:

(x-5)+(x+15)=90°

2x+10=90

2x=80

x=40°

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2 years ago

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I need some help, sooooo... please?

Ivan

<h3>Answer: x+3</h3>

==============================================================

Explanation:

Use a graphing tool like Desmos to plot y = |x+3|

See below.

The graph is a V shaped figure. The vertex is at (-3,0). The interval x > 5 is entirely to the right of this vertex. So we only focus on the right hand side of the V shape.

The line making up this right hand side is the equation y = x+3

Therefore, if x > 5 then y = |x+3| becomes y = x+3

In short, we erase the absolute value lines.

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2 years ago

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kvasek [131]

Answer:

Step-by-step explanation:

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3 years ago

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