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3 years ago

What is the radius of a circle whose equation is (x-7)2+(y-10)2=4

Mathematics

2 answers:

Anestetic [448]3 years ago

8 0

Answer:

Answer is A 2 units

Step-by-step explanation:

Drupady [299]3 years ago

7 0

Did you try the square root of 4? 2?

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What is the approximate perimeter of a semicircle with a radius of 9mm?

Cerrena [4.2K]

Act like it's a whole circle and find the perimeter, then divide by 2.

P = 2 * pi * r

P = 2 * 3.14 * 9

P = 56.52

Now divide by 2:

P = 28.26

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The general manager of a fast food restaurant chain must select 6 restaurants from 11 for a promotional program. How many differ

Arisa [49]

Answer:

Step-by-step explanation:

This question will be solved using the combination formula which is nCr because the order is unimportant and we need the selection.

11C6

11!/(11-6)!*6!

= 462

Therefore the manager can select the restaurant in 462 ways.

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What is 8 minus the quotient of 15 and y

DerKrebs [107]

You would end up with an equation of 8 - y/15.

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3 years ago

What is the GCF of 12 and 48?

denpristay [2]

48 = 12*4

12 = 12*1

The greatest common factor of 12 and 48 is 12

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3 years ago

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You are given the following equation.

saul85 [17]

Answer:

Step-by-step explanation:

Given the equation 4x²+ 49y² = 196

a) Differentiating implicitly with respect to y, we have;

$8x + 98y\frac{dy}{dx} = 0\\98y\frac{dy}{dx} = -8x\\49y\frac{dy}{dx} = -4x\\\frac{dy}{dx} = \frac{-4x}{49y}$

b) To solve the equation explicitly for y and differentiate to get dy/dx in terms of x,

First let is make y the subject of the formula from the equation;

If 4x²+ 49y² = 196

49y² = 196 - 4x²

$y^{2} = \frac{196}{49} - \frac{4x^{2} }{49} \\y = \sqrt{\frac{196}{49} - \frac{4x^{2} }{49} \\} \\$

Differentiating y with respect to x using the chain rule;

Let $u= \frac{196}{49} - \frac{4x^{2} }{49}$

$y = \sqrt{u} \\y =u^{1/2} \\$

$\frac{dy}{dx} = \frac{dy}{du} * \frac{du}{dx}$

$\frac{dy}{du} = \frac{1}{2}u^{-1/2} \\$

$\frac{du}{dx} = 0 - \frac{8x}{49} \\\frac{du}{dx} =\frac{-8x}{49} \\\frac{dy}{dx} = \frac{1}{2} ( \frac{196}{49} - \frac{4x^{2} }{49})^{-1/2} * \frac{-8x}{49}\\\frac{dy}{dx} = \frac{1}{2} ( \frac{196-4x^{2} }{49})^{-1/2} * \frac{-8x}{49}\\\frac{dy}{dx} = \frac{1}{2} ( \sqrt{ \frac{49}{196-4x^{2} })} * \frac{-8x}{49}\\\frac{dy}{dx} = \frac{1}{2} *{ \frac{7}\sqrt {196-4x^{2} }} * \frac{-8x}{49}\\$

$\frac{dy}{dx} = \frac{-4x}{7\sqrt{196-4x^{2} } }$

c) From the solution of the implicit differentiation in (a)

$\frac{dy}{dx} = \frac{-4x}{49y}$

Substituting $y = \sqrt{\frac{196}{49} - \frac{4x^{2} }{49} \\$ into the equation to confirm the answer of (b) can be shown as follows

$\frac{dy}{dx} = \frac{-4x}{49\sqrt{\frac{196-4x^{2} }{49} } }\\\frac{dy}{dx} = \frac{-4x}{49\sqrt{196-4x^{2}}/7} }\\\\\frac{dy}{dx} = \frac{-4x}{7\sqrt{196-4x^{2}}}$

This shows that the answer in a and b are consistent.

6 0

3 years ago