Answer: $51
60 * .15 = 9
60 - 9 = $51
So remember that the distance formula is
.
1.

Distance between (4,-5) and (4,-2) is 3 units.
2.

Distance between (1,1) and (-1,4) is √13 (or 3.61 rounded to the hundreths) units.
Answer:
the correct option is d. 0.02
Step-by-step explanation:
We have the following events:
x: A drought occurd
y: Water rationing.
Therefore, according to the plaster we have:
P [x] = 0.20
P [y | x] = 0.10
Now P [it is a drought and water rationing happens] =
P [x n y] = P [y | x] * P [x] = 0.10 * 0.20 = 0.02
Which means that the correct option is d. 0.02
Answer:
B. 
Step-by-step explanation:





