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Luba_88 [7]
3 years ago
5

What information is needed in order to solve problems using the Pythagorean theorem?

Mathematics
1 answer:
gladu [14]3 years ago
8 0
You would need to know the length of two sides either a2, b2, c2. you would also need to know what sides you are solving for, either one of the legs or hypotenuse. hope this helps, if you know how to solve a Pythagorean theorem problem this should be easy to answer

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Help me please answer
neonofarm [45]

Answer:

Volume of cone = 90 ft³

Step-by-step explanation:

diameter of cone = 6ft

radius of cone = 3ft

height = 10ft

Volume of cone = \frac{\pi r^2h}{3}

V = (3 × 3 × 3 × 10)/3

V = 270/3

V = 90 ft³

3 0
3 years ago
What is the value of x?<br><br><br> PLEASE HELP!!!!!!<br> Enter your answer in the box.<br><br> x =
Effectus [21]

Answer:

20

Step-by-step explanation:

3x+50 = 6x-10( opposite angles are equal)

3x = 60

x = 20

7 0
3 years ago
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A paper company needs to ship paper to a large printing business. The paper will be shipped in small boxes and large boxes. The
tatyana61 [14]

Answer:a+b

Step-by-step explanation:

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6 0
3 years ago
If $315 is invested at an interest rate of 3% per year and is compounded continuously, how much will the investment be worth in
irina [24]

Answer:

\$412.64

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

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3 0
3 years ago
The volume of a compound shape . 10 cm &amp; 12 cm .
olga2289 [7]

Answer:

total volume = (1150/3)pi cm^3

approximate total volume = 1204 cm^3

Step-by-step explanation:

The compound solid looks like it's made up of a cylinder with a base with 10 cm diameter and height of 12 cm and a half sphere with radius 10 cm.

volume of cylinder: (pi)(r^2)h

volume of sphere: (4/3)(pi)r^3

total volume = (pi)(r^2)h + (1/2)(4/3)(pi)r^3

We are given a diameter of 10 cm, so the radius is 5 cm since r = d/2.

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exact total volume = (1150/3)pi cm^3

approximate total volume = 1204 cm^3

3 0
3 years ago
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