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3 years ago

What information is needed in order to solve problems using the Pythagorean theorem?

1 answer:

8 0

You would need to know the length of two sides either a2, b2, c2. you would also need to know what sides you are solving for, either one of the legs or hypotenuse. hope this helps, if you know how to solve a Pythagorean theorem problem this should be easy to answer

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No estimating in this question.

nekit [7.7K]

Driving 350 miles requires

(350 mi) / (10.4 mi/L) ≈ 33.65 L

of petrol.

This amount of petrol would cost

(33.65 L) × (£1.29/L) ≈ £43.41

5 0

3 years ago

2. A circular patio has a diameter of 18 feet. How

lisabon 2012 [21]

Answer: So to cover the patio it would take 255 whole tiles. 254.469 if you want to be exact.

Step-by-step explanation:

When finding flooring needed we are finding for area. We know the formula for finding the area of a circle is A= $\pi r^{2}$ so we plug in our known variables...

we know r because radius is half of diameter and diameter was given in problem. So half of 18 is 9.

r=9

A= $\pi 9^{2}$

A= $\pi$ 81

A=254.469

8 0

3 years ago

(1/6)^×=216 solve for x

zheka24 [161]

$\frac{1}{6}^x=216\\\\
Write\ 216\ as\ (\frac{1}{6})^{-3}\ to\ have\ a\ common\ base\\\\
\frac{1}{6}^x=(\frac{1}{6})^{-3}\\\\
x=-3\\\\Solution\ is\ x=-3.$

4 0

3 years ago

There are 454 grams in a line. There are 16 ounces in a pound.How many grams are in an ounce?

hram777 [196]

Answer:

28.375 (rounded to 29 grams)

Step-by-step explanation:

there are about 454 grams in a pound and 16 ounces in a pound, so to find the relationship we divide 454 by 16 to get 28.375 or about 29 grams

6 0

2 years ago

3x^2 – 8x + 5 = 5x^2

Ghella [55]

Answer:

Step-by-step explanation:

$3x^2 -8x +5 = 5x^2\\\\5x^2 - 3x^2 + 8x -5 =0\\\\2x^2 +8x -5 = 0\\\\$

a = 2, b = 8, c = -5

$x = \frac{-b \pm \sqrt{b^2 -4ac} }{2a}\\\\x = \frac{-8 \pm \sqrt{8^2 - ( 4 \times 2 \times (-5))} }{2 \times 2}\\\\x = \frac{-8 \pm \sqrt{64 +40} }{4}\\\\x = \frac{-8 + \sqrt{64 +40} }{4} \ , \ x = \frac{-8 - \sqrt{64 +40} }{4}\\\\x = \frac{-8 + \sqrt{104} }{4} \ , \ x = \frac{-8 - \sqrt{104} }{4}\\\\x = \frac{-8 + \sqrt{4 \times 26} }{4} \ , \ x = \frac{-8 - \sqrt{4 \times 26} }{4}\\\\x = \frac{-8 +2 \sqrt{26} }{4} \ , \ x = \frac{-8 - 2\sqrt{26} }{4}\\\\$

$x = \frac{-4 + \sqrt{26} }{2} \ , \ x = \frac{-4 - \sqrt{26} }{2}$

8 0

3 years ago