How was data put into the Tabulating Machine?
Answer:
punch cards
The <u>control class</u> acts as a switchboard between the view layer and the domain layer.
Explanation:
As the name suggests, the control class is responsible for performing the control actions. The view layer defines the entities and attributes which have to be viewed and their structural organization.
The domain layer consists of all the entities, attributes, and relations in the data. The control class controls the flow of information between the two layers and performs the operations of filtering and selecting the content to be displayed.
The following cose will be used to copy assignment operator for CarCounter
<u>Explanation:</u>
Complete Program:
#include <iostream>
using namespace std;
class CarCounter
{
public:
CarCounter();
CarCounter& operator=(const CarCounter& objToCopy);
void SetCarCount(const int setVal)
{
carCount = setVal;
}
int GetCarCount() const
{
return carCount;
}
private:
int carCount;
};
CarCounter::CarCounter()
{
carCount = 0;
return;
}
// FIXME write copy assignment operator
/* Your solution goes here */
CarCounter& CarCounter::operator=(const CarCounter& objToCopy)
{
if(this != &objToCopy)
carCount = objToCopy.carCount;
return *this;
}
int main()
{
CarCounter frontParkingLot;
CarCounter backParkingLot;
frontParkingLot.SetCarCount(12);
backParkingLot = frontParkingLot;
cout << "Cars counted: " << backParkingLot.GetCarCount();
cout << endl << endl;
system("pause");
return 0;
}
Answer:
Direct traffics.
Explanation:
This channel refers to those traffics that came directly and without any via.
Answer:
6 2 and 0
Explanation:
This algorithm doesn't work if the list is not ordered ascending.
In this example it is not, and indeed the item "1" is never found.
first cycle: first=0, last=12 so midpoint=6
second cycle: first=0, last=5 so midpoint=2
last cycle: first=0, last=1 so midpoint=0
then last is assigned -1 so the while statement is no longer true.
