1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mrac [35]
3 years ago
9

What is the first step in finding a solution to a problem?

Computers and Technology
2 answers:
Lina20 [59]3 years ago
6 0

Answer:

4: Turn the problem into a question

Explanation:

The first step in solving any problem is to properly define what exactly is the problem.

This is easier said than done simply because we can sometimes only see or notice the symptoms of a problem or the results but not the cause of those symptoms/results. The cause is the real problem which may be very elusive or just too complex to define.

So identifying the actual problem is the most important first step to solving it.

Law Incorporation [45]3 years ago
5 0

Answer:

Can i have a points? Tysmm

You might be interested in
Jane Estroisch works as a manager in a multidomestic firm. She focuses on the long-term questions facing the organization such a
navik [9.2K]

Answer:

b

Explanation:

Tactical. Perhaps she needs yo keep in touch with the board of directors in order to make an strategic planning.

3 0
2 years ago
a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv
Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that  cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

<em>#include <bits/stdc++.h></em>

<em>using namespace std;</em>

<em>// chracter to digit mapping, and the inverse</em>

<em>// (if you want better performance: use array instead of unordered_map)</em>

<em>unordered_map<char, int> c2i;</em>

<em>unordered_map<int, char> i2c;</em>

<em>int ans = 0;</em>

<em>// limit: length of result</em>

<em>int limit = 0;</em>

<em>// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]  </em>

<em>bool helper(vector<string>& words, string& result, int digit, int widx, int sum) { </em>

<em>    if (digit == limit) {</em>

<em>        ans += (sum == 0);</em>

<em>        return sum == 0;</em>

<em>    }</em>

<em>    // if summation at digit position complete, validate it with result[digit].</em>

<em>    if (widx == words.size()) {</em>

<em>        if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {</em>

<em>            if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result</em>

<em>                return false;</em>

<em>            c2i[result[digit]] = sum % 10;</em>

<em>            i2c[sum%10] = result[digit];</em>

<em>            bool tmp = helper(words, result, digit+1, 0, sum/10);</em>

<em>            c2i.erase(result[digit]);</em>

<em>            i2c.erase(sum%10);</em>

<em>            ans += tmp;</em>

<em>            return tmp;</em>

<em>        } else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){</em>

<em>            if (digit + 1 == limit && 0 == c2i[result[digit]]) {</em>

<em>                return false;</em>

<em>            }</em>

<em>            return helper(words, result, digit+1, 0, sum/10);</em>

<em>        } else {</em>

<em>            return false;</em>

<em>        }</em>

<em>    }</em>

<em>    // if word[widx] length less than digit, ignore and go to next word</em>

<em>    if (digit >= words[widx].length()) {</em>

<em>        return helper(words, result, digit, widx+1, sum);</em>

<em>    }</em>

<em>    // if word[widx][digit] already mapped to a value</em>

<em>    if (c2i.count(words[widx][digit])) {</em>

<em>        if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0) </em>

<em>            return false;</em>

<em>        return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);</em>

<em>    }</em>

<em>    // if word[widx][digit] not mapped to a value yet</em>

<em>    for (int i = 0; i < 10; i++) {</em>

<em>        if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;</em>

<em>        if (i2c.count(i)) continue;</em>

<em>        c2i[words[widx][digit]] = i;</em>

<em>        i2c[i] = words[widx][digit];</em>

<em>        bool tmp = helper(words, result, digit, widx+1, sum+i);</em>

<em>        c2i.erase(words[widx][digit]);</em>

<em>        i2c.erase(i);</em>

<em>    }</em>

<em>    return false;</em>

<em>}</em>

<em>void isSolvable(vector<string>& words, string result) {</em>

<em>    limit = result.length();</em>

<em>    for (auto &w: words) </em>

<em>        if (w.length() > limit) </em>

<em>            return;</em>

<em>    for (auto&w:words) </em>

<em>        reverse(w.begin(), w.end());</em>

<em>    reverse(result.begin(), result.end());</em>

<em>    int aa = helper(words, result, 0, 0, 0);</em>

<em>}</em>

<em />

<em>int main()</em>

<em>{</em>

<em>    ans = 0;</em>

<em>    vector<string> words={"GREEN" , "BLUE"} ;</em>

<em>    string result = "BLACK";</em>

<em>    isSolvable(words, result);</em>

<em>    cout << ans << "\n";</em>

<em>    return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/19705654

#SPJ1

3 0
2 years ago
An example of a(n) ____ reconnaissance attack is a user who sends SQL injections to a system in hopes of generating some type of
Elden [556K]
The answer to this question is A
7 0
3 years ago
Read 2 more answers
Use EBNF notation to describe the syntax of the following language constructs.
ZanzabumX [31]

Answer:

Following are the description to the given points:

Explanation:

To resolve basic design restrictions, EBNF has also been developed.This principle was its lack of support can identify repeatings easily. It implies that popular BNF models, like the description of a sequence of replicable elements, are complicated and rely on contra intuitive logical math.

To set a list of words divided by commas (e.g. john, coffee, logic) for instance, we would like to say something like "a list is a word accompanied by a few commas or terms." Through EBNF, they may say so. However, there have been no "many" alternatives in the standard BNF format. So, to describe something such as "a list is a term or a number accompanied by a pair with notation and script," you have to say the same thing. Which functions, although it is difficult, as it specifies a variety of lists instead of a specific list.

Essentially, "john, coffee, logic is John's list, accompanied by coffees or, and logic" would be the earlier link.  That's why in Option (a):

The return statement in Java is:

return ('”‘ (~[“] | ” [”e‘])*);

In option (c), it is the valid statement.

7 0
3 years ago
A variable's ________ describes the kind of values that can be held by the variable, how the variable is stored in computer memo
Shtirlitz [24]
A. Data Type.

Data Types can be integers, strings, chars, shorts, ect, and describes what types of values can be stored.
4 0
2 years ago
Other questions:
  • Calculate the total number of bits transferred if 200 pages of ASCII data are sent using asynchronous serial data transfer. Assu
    5·1 answer
  • Which of the following devices is used to connect a computer to a network
    7·1 answer
  • What is Dailymotion Cloud on the Dailymotion site?
    7·2 answers
  • Technically
    12·1 answer
  • What is the duty of business to contribute to the well-being of society
    12·1 answer
  • What is the location used by users to configure delegate access on their own mailboxes? Backstage view &gt; Account Settings Bac
    12·1 answer
  • What are some best practices for file management
    8·1 answer
  • Meaning and explanation of fortran​
    11·2 answers
  • Debug
    9·1 answer
  • In C language. Print numbers 0, 1, 2, ..., userNum as shown, with each number indented by that number of spaces. For each printe
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!