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Yanka [14]
3 years ago
10

Write the following fractions as decimals. First 2 answer gets 40 points!!!!!

Mathematics
2 answers:
Anna [14]3 years ago
6 0

Answer:

A. .2

B. .03

C. .093

D. .1456

murzikaleks [220]3 years ago
4 0
A .2
B .03
C .093
D .1456
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Can anyone do 4,5 and 6 for me plz
cricket20 [7]

For  question 4, sinA =\frac{a}{c}, cosA= \frac{b}{c}, tan B = \frac{b}{a}, sin J = \frac{j}{l}, cosK = \frac{j}{l}, tanK = \frac{k}{j}.

Question 5. Option a and question 6. Option j

Step-by-step explanation:

Step 1:

The three basic formula needed to solve these questions are:

sin\theta = \frac{oppositeside}{hypotenuse} , cos\theta = \frac{adjacentside}{hypotenuse}, tan\theta= \frac{opposite side}{adjacent side}.

Step 2:

Using the above formula, we solve the following values

sinA = \frac{oppositeside}{hypotenuse}  =\frac{a}{c}.

cosA = \frac{adjacentside}{hypotenuse} = \frac{b}{c}.

tanB= \frac{opposite side}{adjacent side}= \frac{b}{a}.

sinJ = \frac{oppositeside}{hypotenuse} = \frac{j}{l}.

cosK = \frac{adjacentside}{hypotenuse}= \frac{j}{l}.

tanK= \frac{opposite side}{adjacent side}= \frac{k}{j}.

Step 3:

For question 5, The triangle's angle = 23°, opposite side = BC inches and hypotenuse = 4 inches.

sin\theta= \frac{opposite side}{hypotenuse}. sin 23^{\circ}= \frac{BC}{4}, sin23^{\circ} = 0.3907,BC = (0.3907)(4) = 1.5628.

SO BC is 1.5628 inches, rounding this off to the nearest tenth, we get BC = 1.6 inches which is option a.

Step 4:

For question 6, The triangle's angle = 50°, opposite side = QR m the adjacent side = 8.1 m.

tan\theta= \frac{opposite side}{adjacentside}. tan 50^{\circ}=\frac{QR}{8.1}, tan50^{\circ} = 1.1917,QR = (1.1917)(8.1) = 9.65277

SO QR is 9.65277 meters, rounding this off to the nearest tenth, we get QR = 9.7 inches which is option j.

7 0
3 years ago
The path of a projectile launched from a 20-ft-tall tower is modeled by the equation y = -5x2 + 40x + 20. What is the maximum he
Otrada [13]

Answer:

30.49 m

Step-by-step explanation:

To obtain the maximum height, we solve for the value x when dy/dx = 0.

Since, y = -5x² + 40x + 20

dy/dx = d[-5x² + 40x + 20]/dx

dy/dx = -10x + 40

Since dy/dx = 0,

-10x + 40 = 0

-10x = -40

x = -40/-10

x = 4

Substituting x = 4 into the equation for y, we have

y = -5x² + 40x + 20

y = -5(4)² + 40(4) + 20

y = -5(16) + 160 + 20

y = -80 + 160 + 20

y = 80 + 20

y = 100 ft

Since y is in feet, we convert to meters.

Since 1 m = 3.28 ft, 100 ft = 100 ft × 1 m/3.28 ft = 30.49 m

So, the maximum height, in meters  reached by the projectile is 30.49 m

3 0
3 years ago
8 minus the quotient of 15 and Y equals a product of Y and 13
meriva

Translating this verebal statement into a symbolic statement:

8 - 15/y = 13y.

Note: your statement would sound better if written as "8 minus the quotient of 15 and y equals the product of y and 13."

8 0
4 years ago
Help in 5 mins? asap? please?<br>use the net to find the lateral area of the prisim
Softa [21]
Hi there!

We'll be finding the area of the entire middle rectangle (the big one), since that is the lateral area. It has a height of 15 and a length of 18.

15 x 18 = 270

The correct answer is the first option, 270m^2.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

7 0
4 years ago
F(x) = -3x + 7 x = -2
Marat540 [252]

Answer:

X= 1/2

Step-by-step explanation:

-3x+7x=2

4x = 2

4x/4 + 2/4

X= 1/2

8 0
3 years ago
Read 2 more answers
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