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Aleonysh [2.5K]
2 years ago
13

the blue lake trail is 11 3/8 miles long. Gemma has hiked 2 1/2 miles each hour for 3 hours . how far is she from the end of the

trail
Mathematics
1 answer:
Mashutka [201]2 years ago
7 0
It is very important to look at all the information's that are given in the question. Based on those given information's the answer to the question can be easily deduced.
Length of the blue lake trail = 11 3/8 miles
                                            = 91/8 miles
Distance hiked by Gemma per hour = 2 1/2 miles
                                                          = 5/2 miles
Then
Distance hiked by Gemma in 3 hours = (5/2) * 3 miles
                                                             = 15/2 miles
Then
Distance from the end of the trail = (91/8) - (15/2) miles
                                                    = (91 - 60)/8 miles
                                                    = 31/8 miles
                                                    = 3 7/8 miles
So it can be concluded from the above deduction that the distance that is still left for Gemma to cover the trail is 3 7/8 miles. I hope there is nothing complicated in the procedure for you to not understand. 
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Answer:

f(2)=18

Step-by-step explanation:

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3 years ago
PLEASE HELP!! I WILL AWARD BRAINLIEST AND 50 POINTS!!!!!!!!!!!!!!!!!!!!!! For the given picture: a) List all of the triangles th
PIT_PIT [208]

Answer:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters.  If your teacher just wants one, it would be the middle one.  (I assume they’ll want all three, since the letters just name points, not angles.)

1) A) Name of triangle: ABO

B) Exterior AngleS: EAO, BOC and AOD

C) Remote Interior Angles: For EAO, it’s ABO and AOB.  For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO

2) A) Name of triangle: ABC

B) Exterior Angles:EAC

C) Remote Interior Angles: ABO and BCO

3) A) Name of triangle: DOC

B) Exterior Angles: ODH, DOA, COB, and OCG

C) Remote Interior Angles: For ODH, it’s DOC and COD.  For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO.  For OCG, it has CDO and DOC

4) A) Name Of triangle: COB

B) Exterior Angles: AOB, DOC, and OBF

C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB.  For OBF, it’s BOC and OCB

Step-by-step explanation:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters.  If your teacher just wants one, it would be the middle one.  (I assume they’ll want all three, since the letters just name points, not angles.)

1) A) Name of triangle: ABO

B) Exterior AngleS: EAO, BOC and AOD

C) Remote Interior Angles: For EAO, it’s ABO and AOB.  For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO

2) A) Name of triangle: ABC

B) Exterior Angles:EAC

C) Remote Interior Angles: ABO and BCO

3) A) Name of triangle: DOC

B) Exterior Angles: ODH, DOA, COB, and OCG

C) Remote Interior Angles: For ODH, it’s DOC and COD.  For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO.  For OCG, it has CDO and DOC

4) A) Name Of triangle: COB

B) Exterior Angles: AOB, DOC, and OBF

C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB.  For OBF, it’s BOC and OCB

6 0
3 years ago
Create an equation to solve for x using the trapezoid midsegment formula:
Serggg [28]

Answer:

Equation for x:    3x - 6 = \frac{2x - 1 + 25}{2}

x = 9

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GH = 21

Step-by-step explanation:

The midsegment formula for a trapezoid is

GH = \frac{CD + FE}{2}

3x - 6 = \frac{2x - 1 + 25}{2}

6x - 12 = 2x + 24

4x = 36

x = 9

CD = 2x - 1 = 2(9) - 1 = 18 - 1 = 17

GH = 3x - 6 = 3(9) - 6 = 3 = 27 - 6 = 21

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Answer:

the answer is -364

Step-by-step explanation:

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