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andrew11 [14]
4 years ago
11

What is the enviromental problem/issue in the ecosystem?

Chemistry
2 answers:
NARA [144]4 years ago
6 0
- Human Overgrowth
- Land Use
- Nuclear Issues
- Intensive Farming
- Pollution
 - Air
 -Water
 - Land
- Waste
Harrizon [31]4 years ago
6 0
That many plants are during due to the pollution
You might be interested in
How many grams of calcium chloride would you need to make 1 L of solution containing 5 ppm calcium (Ca)?
Tresset [83]

Explanation:

The given data is as follows.

           Volume = 1 L,    Concentration of Ca = 5 ppm or 5 mg/L

As 1 mg = 0.001 g so, 5 mg /L will be equal to 0.005 g/l. Molar mass of calcium is 40.078 g/mol.

Hence, calculate molarity of calcium as follows.

           Molarity of Ca = \frac{\text{given concentration}}{\text{molar mass}}

                                  = \frac{0.005 g/l}{40.078 g/mol}

         Molarity of Ca = 1.25 \times 10^{-4} M

Hence, molarity of CaCl_{2} is 1.25 \times 10^{-4} M. Since, volume is same so, moles of calcium chloride will be 1.25 \times 10^{-4} mol.

Thus, we can conclude that mass of CaCl_{2} will be as follows.

             1.25 \times 10^{-4} \times 110.984       (molar mass of CaCl_{2} = 110.984 g/mol)

               = 0.0138 g

Thus, we can conclude that mass of CaCl_{2} is 0.0138 g.

4 0
3 years ago
3 miles of NaCl in 12 liters of water <br> What is the molarity
lesya [120]

Answer:

12 \: litres \: contain \: 3 \:  \: moles \: of \: sodium \: chloride \\ 1 \: litre \: will \: contain \:  \frac{(1 \times 3)}{12} moles \\  = 0.25 \: mol \:  {l}^{ - 1}

Explanation:

12 \: litres \: contain \: 3 \:  \: moles \: of \: sodium \: chloride \\ 1 \: litre \: will \: contain \:  \frac{(1 \times 3)}{12} moles \\  = 0.25 \: mol \:  {l}^{ - 1}  \\ or : 0.25 \: M

8 0
3 years ago
Read 2 more answers
Label each molecule with the name of its shape. click on the 3d models to rotate the molecules.
SIZIF [17.4K]
??? There's no image?..
6 0
4 years ago
How is Boyle’s law different from Charles’s law?
katrin [286]

Answer:

In Charles law, temperature and volume of the gas are kept at constant pressure. Where as in Boyle's law, pressure and volume of the gas are kept at a constant temperature. In Boyle's law, pressure and volume vary inversely where as, in Charles law, pressure and volume vary directly.

3 0
3 years ago
Is the reaction to produce zinc from zinc sulfide spontaneous under standard conditions? Coupledreaction: ZnS(s) + H2 (g)  Zn(s
finlep [7]

Answer:

The reaction to produce zinc from zinc sulfide is not spontaneous under standard conditions.

Explanation:

Hess's law states: "When one reaction can be expressed as the algebraic sum of others, its heat of reaction is equal to the same algebraic sum of the partial heats of the partial reactions". So Hess's Law is an indirect method of calculating the heat of reaction or enthalpy of reaction when the chemical reaction occurs in one or more than one stage.

Taking into account that ΔG is a state function, which only depends on the initial and final states, its variation in a reaction is calculated by adding the free energies of the reactants and products involved in it when both are in the normal state. That is, at the pressure of 1natm if it is gases or at the concentration of 1 mol / L for substances in liquid solution.

The sum of the fitted equations should give the problem equation. So, if in a "data" reaction a substance is as a reactant and in the reaction that you must obtain is as a product, you must turn the "data" reaction and ΔG will change its sign. In this case, this happen with the reaction 1 (Rxn1):

Rxn1: ZnS (s) → Zn (s) + S (s)          ΔG1°= 201.3 kJ

Rxn2: S (s) + H₂ (g) → H₂S (g)        ΔG2°= -33.4kJ

Adding both reactions (taking into account that certain substances appear sometimes as a reagent and others as a product, so they are totally eliminated if they appear in the same quantities) you get:

ZnS (s) + H₂ (g) → Zn (s) + H₂S (g)

Adding algebraically ΔG1° and ΔG2° you get:

ΔG°= ΔG1° + ΔG2°

ΔG°= 201.3 kJ - 33.4 kJ

ΔG°= 167.9 kJ

If a chemical reaction proceeds with a ΔG <0 the process is  spontaneous. If, on the other hand, ΔG> 0, the reaction is not spontaneous.

Since ΔG>0, <u><em>the reaction to produce zinc from zinc sulfide is not spontaneous under standard conditions.</em></u>

6 0
3 years ago
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