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3 years ago

If a sausage-making machine produces 3,000 sausages in h hours, how many sausages can it produce in m minutes?

Mathematics

1 answer:

Vesnalui [34]3 years ago

4 0

3000 s........h hours
3000/h.........1 hour
3000/60h.......1 minute
3000*m/60h....m minutes

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The table shows the hours Gina worked during October and November. Select ALL correct statements.

Vladimir79 [104]

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3 years ago

When Mischa filled her car's gas tank before beginning a trip, the car's odometer read 44,587 miles. When she stopped for gas ne

pantera1 [17]

Answer:

18.11 miles per gallon

Step-by-step explanation:

Get the miles traveled from the trip odometer, or subtract the original odometer reading from the new one.

Divide the miles traveled by the amount of gallons it took to refill the tank. The result will be your car’s average miles per gallon yield for that driving period.

44,895-44,587 = 308 miles

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3 years ago

The length of a rectangle is three times its width of the perimeter of the rectangle is 40 yd find its length and width

schepotkina [342]

Answer:

Step-by-step explanation:

L= 3W

Perimeter = 2(l+w) = 40

2(3w+w) = 40

2*4w = 40

8w =40

w = 5

l = 3*5 = 15

3 0

3 years ago

Can someone please help me?

adell [148]

Answer:

Step-by-step explanation:

Not 100% sure

8 0

3 years ago

Read 2 more answers

Hi there,<br> I need help to solve the perimeter and the surface area of this shape.<br> Thanks!

leonid [27]

Answer: Perimeter = 6π ≈ 18.84

Area = 15π ≈ 47.10

<u>Step-by-step explanation:</u>

This is a composite of a big semicircle with diameter of 10 --> radius (r) = 5

plus a medium semicircle with diameter of 6 --> r = 3

minus a small semicircle with diameter of 4 --> r = 2

Perimeter of a semicircle = $\dfrac{1}{2}(2\pi r)=\pi r$

$P_{big}=\pi (5)\quad =5\pi\\P_{medium}=\pi (3)\quad =3\pi\\P_{small}=\pi (2)\quad =2\pi\\P_{composite} =5\pi+3\pi -2\pi\\.\qquad \qquad =\large\boxed{6\pi}$

Area of a semicircle = $\dfrac{1}{2}(\pi r^2)$

$A_{big}=\dfrac{1}{2}\pi (5)^2\quad =12.5\pi\\\\A_{medium}=\dfrac{1}{2}\pi (3)^2\quad =4.5\pi\\\\A_{small}=\dfrac{1}{2}\pi (2)^2\quad =2\pi\\\\A_{composite} =12.5\pi+4.5\pi -2\pi\\\\.\qquad \qquad =\large\boxed{15\pi}$

8 0

3 years ago