Evaluate: 481 + 7 + 0.56 =

Genrish500 [490]

0.2(d-b)=0.3b+5-3+0.1d
you first distribute the 0.2 to the d and b in the parentheses, you'll then get
0.2d-0.2b=0.3b+5-3+0.1d
now you make sure that the b variables are with each other on the same side of the equal sign. so you subtract 0.3b from both sides to get
0.2d-0.5b=5-3+0.1d
now do the same thing with the d variables so subtract 0.1d from both sides to get
0.1d-0.5b=5-3
now you can subtract 5-3 which is easy to get
0.1d-0.5b=2
now you have to figure out what d and b equal. so i'll do b first. all you do is use the equation you have now and pretend that d is 0 so substitute the 0 in with the d variable to get
0.1(0)-0.5b=2
now you divide -0.5b from both sides to get
-0.5b/-0.5= b 2/-0.5= -4
so now you know b = -4
now you do sthe sane thing with b substitute with a 0 to get
0.1d-0.5(0)=2
then divide 0.1d from both sides to get
0.1d/0.1=b 2/0.1=20
now you know d = 20
( d=20, b=-4 )

3 0

4 years ago

J is the midpoint of MN. Find MN if JM = 6 3/4

Anna71 [15]

Answer:

(4, 5)

Step-by-step explanation:

7 0

3 years ago

Use GCF and the distributive property to rewrite 56+48

Novosadov [1.4K]

Answer:

8(7+6)

Step-by-step explanation:

56+48

56 = 7*8

48 = 6*8

Factor out the 8

7*8 + 6*8

8(7+6)

8 0

4 years ago

According to a 2013 study by the Pew Research Center, 15% of adults in the United States do not use the Internet (Pew Research C

Pavel [41]

Answer:

a) For this case we can use the binomial model since we assume independent events and the same probability for each trial is the same p =0.15

b) $P(X=0)=(10C0)(0.15)^0 (1-0.15)^{10-0}=0.1969$

c) $P(X=3)=(10C3)(0.15)^3 (1-0.15)^{10-3}=0.1298$

d) $P(X \geq 1)= 1-P(X$

And using the result from part a we got:

$P(X \geq 1)= 1-P(X$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n p)$