Linear equation are the equation which has the power of the unknown variable is 1. The Emily have total 2 number of dimes coin and total 6 number of nickels coin.
<h3>Given information-</h3>Emily has 8 coins in her purse totaling 50 cents
The only kinds of coins she has are nickels and dimes.
<h3>Nickel</h3>A nickel is a coin which has the value equal to the 5 cents.
<h3>Dimes</h3>A dimes is a coin which has the value equal to the 10 cents.
Suppose the number of nickel coin is <em>x </em>and the number of dimes coin is <em>y.</em>
As total coins are 8 . Thus,
......equation 1
As the total value of the cents is 50 and nickel is equal to the 5 cents whereas the dimes is equal to the 10 cents. Thus,
Put the value of the <em>x</em> from the equation 1 in the above equation.
Thus Emily have total 2 number of dimes coin.
Put this value of y in equation 1 we get,
Thus Emily have total 6 number of nickels coin.
Hence the Emily have total 2 number of dimes coin and total 6 number of nickels coin.
Learn more about the coin based problems here;
The rule for g(x) is:
Step-by-step explanation:
Given function is:
When a function f(x) is shifted right or left, b units the new function is written as:
Shifting right
Shifting left
Similarly, when shifting up or down
As our given function is shifted 3 units to the right, it will be written as:
The function is when moved down 3 units, then
Hence
The rule for g(x) is:
Keywords: Function transformation, Functions
Learn more about functions at:
#LearnwithBrainly
Step-by-step explanation:
The rate of the motorboat on still water is 1375
The current rate of the motorboat is 2025
Answer:
a) 0.5.
b) 0.8413
c) 0.8413
d) 0.6826
e) 0.9332
f) 1
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
(a) P(x > 6) =
This is 1 subtracted by the pvalue of Z when X = 6. So
has a pvalue of 0.5.
1 - 0.5 = 0.5.
(b) P(x < 6.2)=
This is the pvalue of Z when X = 6.2. So
has a pvalue of 0.8413
(c) P(x ≤ 6.2) =
In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.
(d) P(5.8 < x < 6.2) =
This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X 5.8.
X = 6.2
has a pvalue of 0.8413
X = 5.8
has a pvalue of 0.1587
0.8413 - 0.1587 = 0.6826
(e) P(x > 5.7) =
This is 1 subtracted by the pvalue of Z when X = 5.7.
has a pvalue of 0.0668
1 - 0.0668 = 0.9332
(f) P(x > 5) =
This is 1 subtracted by the pvalue of Z when X = 5.
has a pvalue of 0.
1 - 0 = 1
