Answer:
C
Step-by-step explanation:
Let the first term be a and the common ratio be r.
ATQ, ar^4=24 and ar^6=144, r=sqrt(6) and a=24/(sqrt(6))^2=24/36=2/3
Answer:
Step-by-step explanation:
in a parallelogram diagonals bisect each other.
so mid points are same.
Let coordinates of D be (x,y)
mid point of AC=midpoint Of BD
(-2+5)/2=(x+3)/2
x+3=-3
x=-3-3=-6
x=-6
(3-3)/2=(2+y)/2
y+2=0
y=-2
so D is (-6,-2)
Area of Parallelogram ABCD is equivalent to the area of rectangle AXBY.
Area of rectangle AXBY= Length AX * Length AB= 3 ft * 4√2 ft = 12√2 sq.ft.
Thus Area of Parallelogram is 12√2 sq.ft.
The density is 0.1019g/cm3