Answer:
Step-by-step explanation:
Whatever number is in Set A, it must also be in Set B and Set C.
The elements in Set A must be an even number and a multiple of 7.
Multiples of 7 from Set A are -7, 14, 21, 42.
The even numbers from these multiples of 7 are 14 and 42.
14, 42
Set A = {−7, −4, 2, 14, 21, 34, 42}
Set B = {even numbers}
Set C = {multiples of 7}
There is only one question asked
Which numbers in Set A are elements of both Set B and Set C,
We need it to be even and a multiple of 7
14 is even and a multiple of 7 and 42 is even and a multiple of 7
4
Explanation:
Since the third term is the sum of the two previous terms
Continuing in like manner
Since
Recall:
The sequence is therefore:
8,-5,3,-2,1,-1,0
The sum of the seven numbers is 4.
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-3
-2+-3=5