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kondaur [170]
3 years ago
11

Write the expression for the following the product of five and two ,added to seven. PLS HELP ME

Mathematics
2 answers:
netineya [11]3 years ago
4 0

Answer:

5 times 2 + 7

Step-by-step explanation:

lorasvet [3.4K]3 years ago
3 0

Answer:

5*2+7

Step-by-step explanation:

i believe thats it

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Read 2 more answers
Express in exponential form 200×75​
GREYUIT [131]

Do you mean exponential form as in scientific notation or as in prime factorization.

Now matter I will do both.

As in scientific notation.

200*75

=150*100

=1.5*10000

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As in prime factorization.

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3 years ago
What is the partial fraction decomposition of StartFraction 8 x + 19 Over (x + 8) (x minus 1) EndFraction? StartFraction 3 Over
hoa [83]

The partial fraction decomposition is \frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

<h3>How to determine the decomposition?</h3>

The fraction is given as:

\frac{8x + 19}{(x + 8)(x - 1)}

Split the fraction as follows:

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{A}{x + 8} + \frac{B}{x - 1}

Take the LCM

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{Ax -A + Bx + 8B}{(x + 8)(x -1)}

Cancel the common factors

8x + 19 = Ax - A + Bx + 8B

By comparison, we have:

Ax + Bx = 8x

-A + 8B = 19

This gives

A + B = 8

-A + 8B = 19

Add both equations

9B = 27

Divide by 9

B = 3

Substitute B = 3 in A + B = 8

A + 3 = 8

Solve for A

A = 5

So, we have:

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

Hence, the partial fraction decomposition is \frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

Read more about partial fraction at:

brainly.com/question/12783868

#SPJ1

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2 years ago
When do I learn when what I what what what
aleksandrvk [35]

Answer:

Think???????????????

6 0
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