Question

Three different ways to put 6(3x + 8) + 32 + 12x

Answer 1

Answer:

Writing 6(3x + 8) + 32 + 12x in 3 different ways:

• w₁ = 18x + 48 + 32 + 12x      

∵ 6(3x + 8) = 18x +48 as distribute law suggests that  a(b + c) = ab + ac

• w₂ = 18x + 80 + 12x              ∵ 48 + 32 = 80

• w₂ = 30x + 80                        ∵ 18x + 12x = 30x

Step-by-step explanation:

As the expression is 6(3x + 8) + 32 + 12x, and we have to write it in three different ways. Using the properties of operations we can write it in three different ways,

Let way one be denoted as w₁

Let way two be denoted as w₂

Let way three be denoted as w₃

So, lets write 6(3x + 8) + 32 + 12x in 3 different ways:

• w₁ = 18x + 48 + 32 + 12x      

∵ 6(3x + 8) = 18x +48 as distribute law suggests that  a(b + c) = ab + ac

• w₂ = 18x + 80 + 12x              ∵ 48 + 32 = 80

• w₂ = 30x + 80                        ∵ 18x + 12x = 30x

Keywords: operation properties, distributive law

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