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Karo-lina-s [1.5K]
3 years ago
6

Three different ways to put 6(3x + 8) + 32 + 12x

Mathematics
1 answer:
Sever21 [200]3 years ago
3 0

Answer:

<em>Writing 6(3x + 8) + 32 + 12x in 3 different ways:</em>

  • w₁ = 18x + 48 + 32 + 12x      

∵ 6(3x + 8) = 18x +48 as distribute law suggests that  a(b + c) = ab + ac

  • w₂ = 18x + 80 + 12x              ∵ 48 + 32 = 80
  • w₂ = 30x + 80                        ∵ 18x + 12x = 30x

Step-by-step explanation:

As the expression is 6(3x + 8) + 32 + 12x, and we have to write it in three different ways. Using the properties of operations we can write it in three different ways,

Let way one be denoted as w₁

Let way two be denoted as w₂

Let way three be denoted as w₃

So, lets write 6(3x + 8) + 32 + 12x in 3 different ways:

  • w₁ = 18x + 48 + 32 + 12x      

∵ 6(3x + 8) = 18x +48 as distribute law suggests that  a(b + c) = ab + ac

  • w₂ = 18x + 80 + 12x              ∵ 48 + 32 = 80
  • w₂ = 30x + 80                        ∵ 18x + 12x = 30x

<em>Keywords: operation properties, distributive law</em>

<em>Learn more about operation properties from brainly.com/question/13754344</em>

<em>#learnwithBrainly</em>

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62.93%

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We have to solve it by a Poisson distribution, where:

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p (x> 3) = 1 - p (x <= 3)

So, we calculate the probability from 0 to 3:

 p (x = 0) = 2.72 ^ (- 4.33) * 4.33 ^ (0) / 0! = 0.01313

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