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Dafna11 [192]
3 years ago
5

LOOK AT THE PICTURE

Mathematics
2 answers:
OleMash [197]3 years ago
6 0

Answer:

I don't think any of the answers here are right. They aren't a proportional relationship since they don't pass through the origin. So I would believe the answer would be C. Sorry if I'm wrong!!

Step-by-step explanation:

I learned about this stuff :D

Svet_ta [14]3 years ago
5 0

Answer:

C, because you would need two numbers to find the slope of the graph.

Step-by-step explanation:

I had to take a minute to understand this question.

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Question 1 (Fill-In-The-Blank Worth 3 points)
goldenfox [79]
Non so che fare il primo a
5 0
2 years ago
The image shows the energy that can be generated from the Earth's water and the pull of the Moon's gravity.
tester [92]

Answer:

It is tidal energy, which is a renewable resource

Step-by-step explanation:

Tidal energy is is the energy produced when interaction of earth water masses and Moon's gravitational pull takes place. when moon's gravitational pull occurs on ocean water, currents and motion is produced in ocean water which leads to rise in water. when earth rotates this rise in water meets the shallow region of water near the shore and hence tide is created. This motion of  rise and fall of water stores energy which is called tidal energy.

Renewal source is one which does not gets depleted and is replenished by nature. It's quantity will not get reduced with consumption.

example is sunlight : sunlight is renewable energy as everyday day this energy is produced . no matter how much it is consumed on earth for a day. Next day it will be again produced by earth.

Since, tides are regularly occurring phenomenon hence they are source of renewable tidal energy produced by them

7 0
2 years ago
Need help ASAP PLEASE!!!!!!!!!!!!!!!
Lena [83]

Answer:

Quartz, Cups

Step-by-step explanation:

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7 0
2 years ago
Need to know the population in 2015
Margarita [4]
\bf P=1110.9e^{kt}\quad 
\begin{cases}
P=1200 &\textit{in thousands}\\
t=2 &\textit{in 2002}
\end{cases}\implies 1200=1110.9e^{k2}
\\\\\\
\cfrac{1200}{1110.9}=e^{2k}\implies ln\left( \frac{1200}{1110.9} \right)=ln(e^{2k})\implies ln\left( \frac{1200}{1110.9} \right)=2k
\\\\\\
\cfrac{ln\left( \frac{1200}{1110.9} \right)}{2}=k\implies 0.0385755\approx k\implies 0.0386\approx k\\\\
-------------------------------\\\\

\bf P=1110.9e^{0.0386t}\qquad 
\begin{cases}
t=14\\
\textit{year 2015}
\end{cases}\implies P=1110.9e^{0.0386\cdot 14}
\\\\\\
P\approx 1907.0747\implies about\ 1,907,075\textit{ once rounded up}
3 0
2 years ago
Good evening, I am taking an Algebra class for the first time after 50 years, and can not remember how to find the point-slope f
Olin [163]
m=-1/5p x 10.4
m=-1/5p x 52/5
m=-52/25p

8 0
3 years ago
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