All categories

2 years ago

Solve this problem : (X-3)^2

Mathematics

2 answers:

krek1111 [17]2 years ago

7 0

Answer:

x^2 - 6x + 9

Step-by-step explanation:

(x - 3)^2

(x - 3)(x - 3)

x^2 - 3x - 3x + 9

x^2 - 6x + 9

Rufina [12.5K]2 years ago

5 0

Answer:x^2-6x+9

Step-by-step explanation:

(x-3)^2=(x-3)(x-3)=x^2-3x-3x+9

Collect like terms

X^2-6x+9

You might be interested in

What is the recursive formula for this arithmetic sequence 6, -24, 96, -384

Artemon [7]

Answer:

Option A. $a_{1} =6$ $a_{n}= a_{n-1}(-4)$

Step-by-step explanation:

The given sequence in the question is 6,-24,96,-384.......n

and we have to give the recursive formula for this arithmetic sequence.

We can re write the sequence to make it more simpler

6,6(-4),(-24)(-4),(96)(-4).......n terms

Now we can say $a_{1} = 6$

and $a_{n}= a_{n-1}(-4)$

Therefore the recursive formula of the sequence is $a_{1} = 6$

$a_{n}= a_{n-1}(-4)$

7 0

3 years ago

ava picks a number greater than 3 tens 6 ones. the number is less than 52. it has more than 6 ones. what could the. number be?

Svetlanka [38]

Any where between 37 and 51

6 0

3 years ago

The shorter leg of a 30 60 90 triangle is 6.4 inches long. Find the perimeter.

kogti [31]

The perimeter is 38.4 inches

8 0

3 years ago

ABCD is a rectangle. AB = 2x + y, BC = x + 2,<br> DC = x + 12, and AD = y + 6. Find AB.<br> =

iren2701 [21]

Answer:

See attached image

Step-by-step explanation:

See attached image

3 0

2 years ago

Please help me as soon as posable!! In hurry!!(24 points)

attashe74 [19]

The sequence is geometric, so

$a_n = r a_{n-1}$

for some constant r. From this rule, it follows that

$a_3 = r a_2 \implies 20 = 2r \implies r = 10$

and we can determine the first term to be

$a_2 = r a_1 \implies 2 = 10 a_1 \implies a_1 = \dfrac15$

Now, by substitution we have

$a_n = r a_{n-1} = r^2 a_{n-2} = r^3 a_{n-3} = \cdots$

and so on down to (D)

$a_n = r^{n-1} a_1 = 10^{n-1} \cdot \dfrac15$

(notice how the exponent on r and the subscript on a add up to n)

4 0

1 year ago