Let S = Sum after 13 years
So = amount invested
t = time in years
i = annual interest rate = .0325
The S = So(1+i)t = $2,200(1.0325)13 = $3,334.21
I can figure out this is a frefall motion.
Starting from rest => Vo = 0
Then, use the equation: d = [1/2]gt^2 => t = √(2d/g)
d = width of a black/clear stripe pair = 5cm = 0.05m
g ≈ 10 m/s^2 (the real value is about 9.81 m/s^2)
t =√(2*0.05m/10m/s^2) = 0.1 s
Answer: approximately 0.1 s
Answer:
yes but no a statistical question is determined by requiring multiple data
Step-by-step explanation:
