X^3 = 216
by taking cubic root for both sides
![\sqrt[3]{x^3} = \sqrt[3]{216}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%20%20%5Csqrt%5B3%5D%7B216%7D%20)
x = 6
Answer:
The largest possible value of n is 11.
(A) is correct option.
Step-by-step explanation:
Given that,
The number with at least two digits,the last number was removed. The resulting number was n smaller than the previous one.
We need to find the largest possible value of n
Using given data,
The smallest number of two digit is 10.
Now, we removed last digit then we get 1 which is equal to 10 divided 10.
So, n = 10
But the largest number of two digit is 99.
We removed last digit then we get 9 which is equal to 99 divided 11.
So, n = 11
Hence, The largest possible value of n is 11.
(A) is correct option.
9-4=-5 would be the smallest answer
