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Alex787 [66]
4 years ago
12

n an elimination reaction, the non-preferred geometry in which the β hydrogen and the leaving group are on the same side of the

molecule is called ____________ periplanar. According to the ____________ rule, the major product in a β-elimination has the more substituted double bond. In an ____________ reaction, the rate depends on only the alkyl halide concentration. The rate of the ____________ reaction increases as the strength of the base increases because the reaction is biolecular and the base appears in the rate equation. Carbocation intermediates are involved in ____________ mechanisms. Polar aprotic solvents increase the rate of the ____________ reactions. Anti periplanar geometry is the preferred arrangement for any alkyl halide undergoing ____________ elimination, regardless of whether it is cyclic or acyclic.
Business
1 answer:
nasty-shy [4]4 years ago
6 0

Answer:

Explanation:

In an elimination reaction, the non-preferred geometry in which the β hydrogen and the leaving group are on the same side of the molecule is called syn periplanar. According to the Zaitev rule, the major product in a β-elimination has the more substituted double bond. In an E1 reaction, the rate depends on only the alkyl halide concentration. The rate of the E2 reaction increases as the strength of the base increases because the reaction is biolecular and the base appears in the rate equation. Carbocation intermediates are involved in E1 mechanisms. Polar aprotic solvents increase the rate of the E2 reactions. Anti periplanar geometry is the preferred arrangement for any alkyl halide undergoing E2 elimination, regardless of whether it is cyclic or acyclic.

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Answer:

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jorgensen high tech incorporated is a calendar-year, accrual-method taxpayer. at the end of year 1, jorgensen accrued and deduct
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If jorgensen high tech incorporated is a calendar-year, accrual-method taxpayer. The accrued bonuses  that jorgensen can  deduct in year 1 under  if  Jorgensen paid the bonuses to the employees on March 1 of year 2. is: $174,000.

<h3>How to find the accrued bonuses?</h3>

Using this formula to find the accrued bonuses

Accrued bonuses = Ken bonus + Jayne bonus + Jill bonus +Justin bonus

Where:

Ken bonus =$69,600

Jayne bonus =$52,200

Jill bonus = $34,800

Justin bonus =$17,400

Where:

Let plug in the formula

Accrued bonuses= $69,600 + $52,200 + $34,800+ $17,400

Accrued bonuses = $174,000

Therefore the accrued bonuses is the amount of $174,000.

Learn more about accrued bonuses here:brainly.com/question/18089674

#SPJ1

The complete question  is:

jorgensen high tech incorporated is a calendar-year, accrual-method taxpayer. at the end of year 1, jorgensen accrued and deducted the following bonuses for certain employees for financial accounting purposes. $69,600 for ken. $52,200 for jayne. $34,800 for jill. $17,400 for justin. how much of the accrued bonuses can jorgensen deduct in year 1 under the following alternative scenarios?

Jorgensen paid the bonuses to the employees on March 1 of year 2.

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