Answer:
51.96 mm² approximately
Step-by-step explanation:
the first thing you should know is that the area of a rectangle is base*height sin of (
the included angle i.e
Arectangle= bh sin90° since all angles of a rectangle are equal then the included angle is 90°
<em>Arectangle= bh sin90° since sin90 is 1 we simply use the equation bh because multiplying bh by one is bh. bearing this in mind , the area of the parallelogram can be calculated as:</em>
Aparallelogram= bh sin of sin of the included angle
Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°
Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866
Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866Aparallelogram=51.96 mm² approximately
Answer:
A. Obtuse
Step-by-step explanation:
Well we can cross out C and D just by looking at the triangle because the triangle is not equal and there is no right angle.
Also it is not B an acute because not all the angles are acute.
Hence, the answer is A. Obtuse
Answer:
6,360 yd.
Step-by-step explanation:
To find area you multiply length times width (l*w)
120 times 53
6,360 yd
Hope I helped!! :)
Brainliest??
Have a good night/day/afternoon!!
These three angles are on a line so must total 180°.
So 180-(52+58)=
180-110=70
So angle q is 70°.
