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Alika [10]
3 years ago
6

What volume would 0.358 moles of nitrogen gas (N2) occupy at STP?

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
7 0

<em>Nitrogen gas exists as a diatomic molecule,</em><em>(</em><em>N2</em><em>)</em><em>.</em>

<em>S</em><em>o</em><em>,</em><em>14 g is 0.5 mole of N2, and occupies about 11.2 L at STP.</em>

asambeis [7]3 years ago
6 0

Answer:

8.02L

Step-by-step explanation:

volume of any gas element = 22.4 L

therefore ; 22.4L x 0.358 mol = 8.02L

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Now, by the law of sine,

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⇒ AC = \frac{10}{2} = 5

By Pythagoras,

CB^2 = AB^2 - AC^2=10^2 - 5^2 = 100 - 25 = 75

⇒ CB = \sqrt{75} =8.66025403784\approx 8.66



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