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Zanzabum
3 years ago
9

Suppose that the distribution of IQ's of North Catalina State University's students can be approximated by a normal model with m

ean 130 and standard deviation 8 points. Also suppose that the distribution of IQ's of Chapel Mountain University's students can be approximated by a normal model with mean 120 and standard deviation 10 points. Question 1. You select a student at random from each school. Determine the probability that the North Catalina State University student's IQ is at least 5 points higher than the Chapel Mountain University student's IQ.
Mathematics
1 answer:
konstantin123 [22]3 years ago
6 0

Answer:

The required probability is 0.6517

Step-by-step explanation:

Consider the provided information.

North Catalina State University's students can be approximated by a normal model with mean 130 and standard deviation 8 points.

μ₁ = 130 and σ₁ = 8

Chapel Mountain University's students can be approximated by a normal model with mean 120 and standard deviation 10 points.

μ₂ = 120 and σ₂ = 10

As both schools have IQ scores which is normally distributed, distribution of this difference will also be normal with a mean of μ₁-μ₂ and standard deviation will be \sqrt{\sigma_1^2+\sigma_2^2}

Therefore,

μ = 130-120=10

\sigma = \sqrt{8^2+10^2}=12.806

Now determine the probability of North Catalina State University student's IQ is at least 5 points higher than the Chapel Mountain University student's IQ:

z=\frac{\bar x-\mu}{\sigma}

z=\frac{5-10}{12.806}\approx-0.39

Now by using the z table we find the z- score of -0.39 is 0.6517.

Hence, the required probability is 0.6517

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3 years ago
Malik has a bag with 7 green marbles and 3 black marbles.
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1) Probability: 7/30 (or 23.3%)

2) Probability: 21/100 (or 21.0%)

Step-by-step explanation:

1)

At the beginning, there are 10 marbles in total in the bag, of which 7 are green and 3 are blacks.

So the probability of choosing a green marble as first is:

p(g)=\frac{7}{7+3}=\frac{7}{10}

Then, after he picked a green marble, there are only 9 marbles left in the bag, of which 6 are green and 3 are black. Therefore, at the second time, the probability of choosing a black marble will be

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p(gb)=p(g)p(b)=\frac{7}{10}\cdot \frac{1}{3}=\frac{7}{30}

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2)

In this second case, the same experiment is repeated by this time the first ball is put back into the back after the  first draw.

The probability that Malik will draw a green marble at the first attempt is the same as before:

p(g)=\frac{7}{7+3}=\frac{7}{10}

Later, the green marble is put back in the bag, so we still have 7 green marbles and 3 black marbles. Therefore, the probability of choosing a black marble at the second draw is

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p(gb)=p(g)p(b)=\frac{7}{10}\cdot \frac{3}{10}=\frac{21}{100}

In percentage, \frac{21}{100}\cdot 100 = 21.0\%

3)

The probability in the second case is lower because in the second case, the green marble is put back into the bag after the first draw, therefore at the second draw the probability of choosing a black marble is less than the first case (because in the 2nd case, there are more marbles in total to choose from, so the probability of choosing a black marble will be less).

Learn more about probability:

brainly.com/question/5751004

brainly.com/question/6649771

brainly.com/question/8799684

brainly.com/question/7888686

#LearnwithBrainly

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