Answer:
Jay's age = 13, 12, or 23
Step-by-step explanation:
Let <em>x </em>and <em>y </em>represent the tens and units of Jay's age
We are given that his older brother's age = yx where;
xy + xy + xy = 3x3y is a 2 digit number of tens 3x and units 3y
Therefore, 3x < 10, and 3y < 10, which gives, <em>x</em> and <em>y </em>are each less than 3
Where, x < y given that Jay is the younger of the two brothers
We can have;
x = 1, 2, and y = 3, or 2, y = 3
Therefore, Jays age can be 13, 12, or 23, his brothers age can then be 31, 21, or 32
