For you to be able to answer this you might need a tall numberline
All steps that Marcie did are right, but she forgot to change sign in last step.
Consider the inequality
![-2(x - 5) -12 \le 4 + 6(x + 3).](https://tex.z-dn.net/?f=%20-2%28x%20-%205%29%20-12%20%5Cle%204%20%2B%206%28x%20%2B%203%29.)
Then
![-2x+10-12 \le 4 + 6x+18.](https://tex.z-dn.net/?f=%20-2x%2B10-12%20%5Cle%204%20%2B%206x%2B18.)
Group the numbers:
![-2x-2 \le 6x+22.](https://tex.z-dn.net/?f=%20-2x-2%20%5Cle%206x%2B22.)
Separate terms with x and without x in different sides:
![-2x-6x \le 22+2.\\-8x\le 24.](https://tex.z-dn.net/?f=%20-2x-6x%20%5Cle%2022%2B2.%5C%5C-8x%5Cle%2024.)
The coefficient at x is -8 and it is negative, then dividing the inequality by -8 you have to change sign in opposite:
![x\ge -3.](https://tex.z-dn.net/?f=%20x%5Cge%20-3.%20)
Answer: Marcie forgot to change sign in last step.
If you are given that b = 2, then just plug it in:
![2(2)-4 = 4-4 = 0](https://tex.z-dn.net/?f=2%282%29-4%20%3D%204-4%20%3D%200)
So, your final answer is
0.
Answer:
a>4 or a < 8
Step-by-step explanation:
We can start with the inequality on the left
-a + 2(4+3a) > 28
expand using the distributive property
-a + 8 + 6a > 28
5a + 8 > 28
subtract 8 from both sides to isolate the variable and its coefficient
5a > 20
divide both sides by 5 to isolate a
a > 4
moving on to the inequality on the right
2a - (3a+4) > -12
treat the minus sign as a -1
2a + (-1)(3a+4) > - 12
expand
2a - 3a - 4 > - 12
-a - 4 > -12
add 4 to both sides to isolate a and its coefficient
-a > - 8
multiply both sides by -1 but change the sign because we are multiplying by a negative number
a < 8
Answer:
V = pi 36 units^3
V =113.04 units^3
Step-by-step explanation:
The volume of a cylinder is given by
V = pi r^2 h
V = pi ( 2) ^2 *9
V = pi 36
Letting pi = 3.14
V =113.04