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OLga [1]
4 years ago
5

Which equation shows a correct relationship of trigonometric functions?

Mathematics
2 answers:
AnnyKZ [126]4 years ago
7 0

Answer:

\frac{\sin(x)}{\cos(y)}=1

Step-by-step explanation:

From the given right triangle.

x+y=90\degree

This implies that;

\sin(x)=\cos(y)

Because the two angles are complementary.

We divide both sides by \cos(y) to obtain;

\frac{\sin(x)}{\cos(y)}=\frac{\cos(y)}{\cos(y)}

We simplify to get;

\frac{\sin(x)}{\cos(y)}=1

musickatia [10]4 years ago
6 0

\frac{sin(x)}{cos(y)} = 1

<u>Try it on a calculator.</u>

x + y = 90

if x = 30 and y = 60

\frac{sin(30)}{cos(60)}= 1

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(-2.1m-5)+(3m-7)<br> Find the sum
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Answer:

0.9 m − 12

Note:

Since there is no y value m can not be determine. Therefore finding the sum here can not be determined so instead you can try simplifying

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3 years ago
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In how many different orders can you line up 6 cards on a table?
Harrizon [31]
You simply do 6x5x4x3x2x1 :)
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4 years ago
What is 8.25 as a fraction in simplest form?
vekshin1
8 is a whole number, so this will be the whole number part of our mixed number.

0.25 is a decimal, where 25 is in the HUNDREDths place, so we write 25 as a fraction over 100.

\sf\dfrac{25}{100}

Simplify by dividing 25 to the numerator and denominator.

\sf25\div25=1
\sf100\div25=4

So our fraction is \sf8\dfrac{1}{4}

0.55 is a decimal, where 55 is in the HUNDREDths place, so we write 55 as a fraction over 100.

\sf\dfrac{55}{100}

Simplify by dividing 5 to the numerator and denominator.

\sf55\div5=11
\sf100\div5=20

So our fraction is \sf\dfrac{11}{20}

\sf\dfrac{5}{8}

To convert this to a decimal, just divide 5 / 8

\sf5\div8=0.625
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Noise levels at 3 airports were measured in decibels yielding the following data:
Shalnov [3]

Answer:

a)  The 90% confidence interval for the mean noise level at such locations      

  (112.46 , 163.54)

b) The critical value that should be used in constructing the confidence interval

Z₀.₁₀ = 1.645

Step-by-step explanation:

<u><em>Step(i)</em></u> :-

Noise levels at 3 airports were measured in decibels yielding the following data

108   146   160

Mean of given data

         x^{-} = \frac{108+146+160}{3} = 138

x          :     108   146   160

x-x⁻      :      -30   8       22

(x-x⁻ )² :     900   64     484

Variance  σ ² = ∑(x-x⁻ )²/ n-1

                                        = \frac{900+64+484}{3-1}= 724

Standard deviation  

                σ = √724 = 26.90

<u><em>Step(ii):</em></u>-

The 90% confidence interval for the mean noise level at such locations                        

       (x^{-} - Z_{0.90} \frac{S.D}{\sqrt{n} } , (x^{-} + Z_{0.90} \frac{S.D}{\sqrt{n} } )

The critical value that should be used in constructing the confidence interval

Z₀.₁₀ = 1.645

         (138 - 1.645 \frac{26.90}{\sqrt{3} } , (138 + 1.645 \frac{26.90}{\sqrt{3} } )

        ( 138 - 25.54 , 138 + 25.54 )

        (112.46 , 163.54)

4 0
3 years ago
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