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Gelneren [198K]
3 years ago
9

What is the surface area of a mini basketball with a circumference.of 25 and radius of 4

Mathematics
1 answer:
Nonamiya [84]3 years ago
4 0
The formula to find the surface area of a sphere is A=4(3.14)r². So if you plug in the data you would get,
A=4(3.14)4²
A=(12.56) (16)
A=200.96
You mught want to check over it so you will be able to solve it for yourself the next time you have this question. 

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What single decimal multiplier would you use to decrease by 19% followed by a 17% decrease?
krok68 [10]

Answer:

0.81 & 0.83

Step-by-step explanation:

3 0
3 years ago
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In your US History class, you have scores of 78, 89, 87 and 96 on the first four tests. To get a B, the average of the five test
Vaselesa [24]
Well, since it is asking for an average, we have to add
78+89+87+96=
350... then we divide by 4
which would be 87.5 which IS greater than 80 :)
and less than 90 :)

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A horizontal line on a distance-time graph indicates ________.
xxMikexx [17]
A distance-time graph tells us how far an object has moved with time. The steeper the graph, the faster the motion. A horizontal line means the object is not changing its position - it is not moving, it is at rest. A downward sloping line means the object is returning to the start.
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3 years ago
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Square ABCD has side length a. Half circles with
Inga [223]

The area of the shaded region is 0.215a^2

<h2>Area of composite objects</h2>

The area of the shaded region is expressed according to the formula:

  • A = A_s - A_c

Get the area of the square As

As = a²

A_c = \pi (0.5a)^2\\&#10;A_c = 0.785a^2

Take the difference in the areas

Area of the shaded part = a^2-0.785a^2\\&#10;

Area of the shaded part = 0.215a^2

Hence the area of the shaded region is 0.215a^2

Learn more on area of composite objects here: brainly.com/question/22716761

7 0
3 years ago
Find the length of the height of the right trapezoid shown below, if it has the greatest possible area and its perimeter is equa
Artyom0805 [142]

Answer:

The height of the right trapezoid is   \frac{6}{5+\sqrt{3}}\ units

Step-by-step explanation:

Let

x ----> the height of the right trapezoid in units

we know that

The perimeter of the figure is equal to

P=AB+BC+CD+DH+HA

we have

P=6\ units

AB=BC=CH=HA=x ---> because is a square

substitute

6=x+x+CD+DH+x

6=3x+CD+DH -----> equation A

<em>In the right triangle CDH</em>

sin(30\°)=\frac{CH}{CD}

sin(30\°)=\frac{1}{2}

so

Remember  that CH=x

\frac{1}{2}=\frac{x}{CD}

CD=2x

tan(30\°)=\frac{CH}{DH}

tan(30\°)=\frac{\sqrt{3}}{3}

so

\frac{\sqrt{3}}{3}=\frac{x}{DH}

DH=x\sqrt{3}

substitute the values in the equation A

6=3x+CD+DH -----> equation A

CD=2x

DH=x\sqrt{3}

6=3x+2x+x\sqrt{3}

6=5x+x\sqrt{3}

6=x[5+\sqrt{3}]

x=\frac{6}{5+\sqrt{3}}\ units

5 0
3 years ago
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