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nalin [4]
4 years ago
6

How do the images help express one way technology has changed modern protest in China?

Mathematics
1 answer:
Rus_ich [418]4 years ago
3 0

Where are the images?

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If 10 workers, working for 4 hours complete the work in 12 days, in how many days will 8 workers working for 6 hours complete th
liq [111]

Answer:

As per the question, 10 workers working for 4 hours a day complete their work = 12 days. 1 person working for 1 hour a day complete the work = 12×10×4 days. Thus, the 8 persons working for 6 hrs a day complete their work in 10 days.

Step-by-step explanation:

hope it helps

please mark brainliest

4 0
3 years ago
The function given represents the temperature of a sauna set to 180°F. The temperature goes up and down throughout the day. Find
nasty-shy [4]

Answer:

The answer is below

Step-by-step explanation:

Given the function as:

f(x)=5sin(πx / 15)+180,

a) The angular frequency (ω) = 2π * frequency

but ω = π/15, hence:

π/15 = 2π * frequency

frequency = (π/15)/2π

frequency = 1/30 hertz

Period (T) = 1/frequency = 1/(1/30) = 30 seconds

b) The period is 30 seconds. This means that it reaches the maximum temperature every 30 seconds.

In one hour (3600 s), the number of times the function reaches a maximum temperature = 3600 s / 30 s = 120

3 0
3 years ago
The formula for the circumference of a circle is C=2(pie)(r) Determine the circumference when the radius r is 10 cm.
QveST [7]

the formula for the circumference of a circle is

<span>C = 2 × π × r      or  C = π × D </span>

<span>If either r or D is known, you can calculate the circumference by simply substituting the known value for r or D in the formula. Use 3.14 for π. 
</span>RADIUS = 10DIAMETER = 20
C IS THE ANSWER

4 0
3 years ago
Joe has to build a wall that has 10 rows of bricks.
pentagon [3]

Answer:

1420 bricks

Step-by-step explanation:

10 rows x 142 bricks in each row = 1420 bricks

4 0
3 years ago
Read 2 more answers
Solve each equation (Polynomial equations)
lesya [120]

{ {e}^{x} }^{2}  =  \frac{1}{ {e}^{2} } \times  {e}^{3x}  \\ \Leftrightarrow  { {e}^{x} }^{2}  =  {e}^{ 3x}  \times  {e}^{ - 2}  \\ \Leftrightarrow  { {e}^{x} }^{2}  =  {e}^{3x - 2}  \\ \Leftrightarrow  {x}^{2}  = 3x - 2 \\ \Leftrightarrow  {x}^{2}  - 3x + 2 = 0 \\ \Leftrightarrow (x - 1)(x - 2) = 0 \\ x = 1 \: \vee \: x = 2 \\  \\ {32}^{ {x}^{2} - 2x }  =  \frac{1}{ {4}^{x} } \\  \Leftrightarrow  {( {2}^{5} )}^{ {x}^{2} - 2x }  = {2}^{ - 2x}  \\ \Leftrightarrow  {2}^{5 {x}^{2} - 10x }  =  {2}^{ - 2x}  \\ \Leftrightarrow 5 {x}^{2}  - 10x =  - 2x \\ \Leftrightarrow 5 {x}^{2}    - 8x = 0 \\ \Leftrightarrow x(5x - 8) = 0 \\ \Leftrightarrow x = 0 \: \vee \: x =  \frac{8}{5}  \\  \\  { {e}^{x} }^{3}  =  {2}^{2x} \\ \Leftrightarrow  {x}^{3}  =  ln( {2}^{2x} )  \\ \Leftrightarrow  {x}^{3}  - 2x ln(2)  = 0 \\ \Leftrightarrow x( {x}^{2}  - 2 ln(2) ) = 0 \\ \Leftrightarrow x = 0 \:\vee \:  {x}^{2}  = 2 ln(2)  \\ \Leftrightarrow x = 0 \:\vee \: x =  \sqrt{2 ln(2) }  \:\vee \: x =  -  \sqrt{2 ln(2) }

8 0
4 years ago
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