Area of Triangle:
A = 1/2 bh = 1/2 (5)(12) = 30 m^2
Area of semicircle:
A = 1/2 π r^2 = 1/2 π 6^2 = 18<span>π m^2
Area of figure = </span>Area of semicircle + Area of Triangle
Area of figure = 18π + 30 m^2
Answer is C.
18π + 30 m^2
75% of 12 can be represented with the equation 75/100=x/12
Then to solve
75(12)= 100x
900 = 100x
9=x
So the distance from the school to the park is 9 miles.
Val covers greater distance because 2 3/5 x 4 = 10 2/5. Bill only ran 10 miles so Val covered 2/5 more miles than him.