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Ymorist [56]
3 years ago
5

Sean’s age and Helen’s age are in the ratio of 3:5. Two years ago, Helen was twice as old as Sean was then. Find their present a

ges.
Mathematics
1 answer:
PolarNik [594]3 years ago
3 0
Lets Sean's age be x
Helen's age by y
x/y=3/5
x=3/5y

Second equation
2(x-2)=y-2

on solving u get Helen as 10 and Sean as 6
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Answer:

Least common multiple:

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Step-by-step explanation:

Approach 1. Integer numbers prime factorization:

578 = 2 × 172;

11 is a prime number, it cannot be broken down to other prime factors;

Multiply all the prime factors, by the largest exponents.

Least common multiple:

lcm (578; 11) = 2 × 11 × 172;

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Numbers have no common prime factors: 6,358 = 578 × 11.

Integer numbers prime factorization

Approach 2. Euclid's algorithm:

Calculate the greatest (highest) common factor (divisor), gcf, hcf, gcd:

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This is the greatest common factor (divisor).

Least common multiple, formula:

lcm (a; b) = (a × b) / gcf, hcf, gcd (a; b);

lcm (578; 11) =

(578 × 11) / gcf, hcf, gcd (578; 11) =

6,358 / 1 =

6,358;

lcm (578; 11) = 6,358 = 2 × 11 × 172;

8 0
2 years ago
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