16 as 4x4 = 16 because there are 4 books and 4 available slots
Answer:
The correct answer is d because m<3 is supplementary (meaning the angles add to 180°) to m<4. It's easy to spot two supplementary angles because they will form a linear line.
The answer is D
There isn't a way to show work other than drawing a number line
Answer:
Option A, Option B and option D
Step-by-step explanation:
㏒₂ 72 - ㏒₂ 3 = ㏒₂ (72 ÷ 3)
= ㏒₂ 24
2 ㏒₂ 2 + log₂ 6 = log₂ 2² + log₂ 6
= log₂ 4 + log₂ 6
= log₂ (4*6)
= log₂ 24
log₂ 6 + log₂ 4 = log₂ (6*4)
= log₂ 24
Answer:
![\pm 9in^2](https://tex.z-dn.net/?f=%5Cpm%209in%5E2)
Step-by-step explanation:
We are given that
Radius of end of a log, r= 9 in
Error,
in
We have to find the error in computing the area of the end of the log by using differential.
Area of end of the log, A=![pi r^2](https://tex.z-dn.net/?f=pi%20r%5E2)
![\frac{dA}{dr}=2\pi r](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdr%7D%3D2%5Cpi%20r)
![\frac{dA}{dr}=2\pi (9)=18\pi in^2](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdr%7D%3D2%5Cpi%20%289%29%3D18%5Cpi%20in%5E2)
Now,
Approximate error in area
![dA=\frac{dA}{dr}(\Delta r)](https://tex.z-dn.net/?f=dA%3D%5Cfrac%7BdA%7D%7Bdr%7D%28%5CDelta%20r%29)
Using the values
![dA=18\pi (\pm 1/2)](https://tex.z-dn.net/?f=dA%3D18%5Cpi%20%28%5Cpm%201%2F2%29)
![\Delta A\approx dA=\pm 9in^2](https://tex.z-dn.net/?f=%5CDelta%20A%5Capprox%20dA%3D%5Cpm%209in%5E2)
Hence, the possible propagated error in computing the area of the end of the log![=\pm 9in^2](https://tex.z-dn.net/?f=%3D%5Cpm%209in%5E2)