1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VashaNatasha [74]
2 years ago
13

Respond ASAP please I need this badly I will be giving brainlest thanks and all stars

Mathematics
1 answer:
DaniilM [7]2 years ago
3 0

Answer:

Growth and 108.5%

Step-by-step explanation:

You might be interested in
What do we get when we break apart 46+26 using place value?
SCORPION-xisa [38]
Tenth blocks   ones blocks
                              
l l l l l l l           o o
6 0
3 years ago
At Centertown Middle School, 25% of the 124 students Mrs. Wade teaches buy their lunches in the cafeteria.
cluponka [151]

Out of 124 students, only 31 students are taught to buy their lunches in the cafeteria.

<u>Step-by-step explanation:</u>

It is given that,

The 25% of 124 students are taught to buy their lunches in cafeteria.

Therefore, the total number of students taught to buy their lunches in cafeteria is 25% of 124.

<u>To find the number of students who are capable to buy lunches in cafeteria:</u>

  • Replace the % symbol into the numeric form.
  • The % is represented by 1 ÷ 100.

The 25% of 124 students is written as,

⇒ 25×(1/100)×124

⇒ (1/4)×124

⇒ 31

The number of students taught to buy lunches in the cafeteria out of 124 students is 31 students.

5 0
3 years ago
Match the terms to their definition. 1. part-whole ratio a ratio comparing a portion of a whole quantity to the whole quantity 2
dem82 [27]

Answer:

They're already matched... at least they way you typed it.

Step-by-step explanation:

A ratio is a comparison of two numbers as a fraction or quotient. A part-whole ratio is a ratio comparing a part of something to the whole thing. A part-part ratio is ratio comparing two different parts of one whole.

4 0
2 years ago
Solve this system of linear equations. Separate
Elanso [62]

Answer:

(-3, -3)

Step-by-step explanation:

1.) Rewrite the second equation so 3y is on one side of the equation:

3y=6+5x

2.) Substitute the given value of 3y (replacing 3y with 6+5x, since we know they equal each other) into the equation 17x=-60-3y

Should end up with this:

17x=-60-(6+5x)

3.) Solve 17x=-60-(6+5x)

Calculate Difference: 17x=-66-5x

Combine Like Terms: 22x = -66

Divided both sides by 22 to isolate and solve for x: -3

So We know x=-3, now we got to find the y value. We can use either the first or second equation to find y value, so lets use the second.

3y=6+5x

1.) We know that x=-3, so we can simply substitute x in the equation

3y=6+5x with -3

3y=6+5(-3)

2.) Solve 3y=6+5(-3)

Combine Like Term: 3y=6+-15

Combine Like Term Even More: 3y= -9

Divide by 3 on both sides to isolate and solve for y: y=-3

So now we know y=-3 and once again we know x=-3, so if we format that

(-3,-3)

^  ^

x  y

4 0
3 years ago
50a3 + 10a2
Lady_Fox [76]
50a^3+10a^2\\\\50a^3=10\cdot5\cdot a^2\cdot a=10a^2\cdot5a\\\\50a^3+10a^2=10a^2\cdot5a+10a^2\cdot1=\huge\boxed{10a^2(5a+1)}\to\boxed{A}
3 0
3 years ago
Read 2 more answers
Other questions:
  • What is 6829 km expressed in scientific notation?
    13·2 answers
  • 5x+6y=13;-5x+2y=11. how do I solve this
    6·1 answer
  • Solve each equation *<br><br> Captionless Image<br> a<br> b<br> c<br> d
    12·1 answer
  • What is the solution of 2(x + 4) - x = 15?<br><br> please solve in a easy way
    12·2 answers
  • Which number is greater [-6.809]___[-6.812]
    13·2 answers
  • Which choice is equivalent to the expression below?
    13·1 answer
  • Add -4 + (-15). plz hurry................
    5·2 answers
  • Question attached,
    8·1 answer
  • How long can i holdd me pee because my brother is in the bathroom
    9·2 answers
  • Which statement best describes how to determine whether f(x) = x² – X + 8 is an even function?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!