If you were to show the strength of an attraction near one end of a magnet, you would be showing

1 answer:

5 0

Since it is only near one end of a magnet, what is being shown is the magnetic force of the magnet. The magnetic force is shown between the interaction of an object with an electric field. The object has to be moving to induce a change in the electric field and experience magnetic force.

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Seven times a number is 5600. what is the number?

Vika [28.1K]

To do this you need to work backwards. if you note the number as 'n' you can put
7n = 5600
to find n you simply divide both sides by 7 getting
n = 5600/7
n = 800

5 0

3 years ago

Read 2 more answers

HELP PLS TT^TT 20 POINTS

ki77a [65]

Answer:

Through ASA axiom.

Step-by-step explanation:

It should be by ASA axiom.

The ASA Theorem says: If two angles and the non-included side of one triangle are congruent to the corresponding parts of another triangle, the triangles are congruent.

5 0

2 years ago

Please show your work! Thankyou!

ZanzabumX [31]

Log₄(y+2) = 3, transform it into exponent form:

(y+2) = 4³
y+2 = 64
y= 62

5 0

3 years ago

lena works for 34 hours from monday to friday at her normal rate of pay ,on saturdays she gets an overtime rate of pay ,the over

kifflom [539]

Answer: £ 8

Step-by-step explanation:

Total hours Lena works from Monday to Friday = 34 hours

Hours she works on Saturdays = 4

Overtime rate of Saturday = 1.5 times her normal rate

Let x be the normal rate.

Then , Her total earning = $34 x + 4 \times(1.5x) =34x+6x=40x$

Since her total earnings for week = £ 320

So,

$320=40x\\\\\Rightarrow\ x=\dfrac{320}{40}\\\\\Rightarrow\ x=8$

Thus, her normal rate of pay per hour = £ 8

7 0

3 years ago

Orthogonalizing vectors. Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, a

jeka57 [31]

Answer:

$\\ \gamma= \frac{a\cdot b}{b\cdot b}$

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if $b \neq 0$ . Recall that given two vectors a,b a⊥ b if and only if $a\cdot b =0$ where $\cdot$ is the dot product defined in $\mathbb{R}^n$ . Suposse that $b\neq 0$ . We want to find γ such that $(a-\gamma b)\cdot b=0$ . Given that the dot product can be distributed and that it is linear, the following equation is obtained