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Sindrei [870]
3 years ago
13

1. 205.5m=____mm A.205,500 B.0.2055 C.20.55 D.20,550

Mathematics
2 answers:
zvonat [6]3 years ago
8 0
I think the answer is C though i'm not entirely sure please tell me I'm right or I'm wrong
AysviL [449]3 years ago
3 0
The answer would be A. 205,500 

To convert m<span> to </span>mm<span> use the following formula:</span>
1 m equals 1000 mmSo, to convert 205.5 m to mm, multiply 1000 by 205.5 
205.5 m = 1000 * 205.5 mm = 205500 mm <----- answer
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Solve for m. 2G/K=5/M
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Use matrices to determine the coordinates of the vertices of the reflected figure. Then graph the pre-image and the image on the
Troyanec [42]

Answer:

The coordinates of the vertices of the reflected figure are :

R' is (5 , -2) , S' is (3 , 5) , T' is (-7 , 6) ⇒ the right answer is (d)

Step-by-step explanation:

* When you reflect a point across the line y = x, the x-coordinate

 and y-coordinate change their places.

- If the point is (x , y) then its image is (y , x)

* If you reflect over the line y = -x, the x-coordinate and y-coordinate

 change their places and their signs

- If the point is (x , y) then its image is (-y , -x)

* Lets study the matrix of the reflection  about the line y = x

- The matrix of the reflection about the line y = x is

 \left[\begin{array}{cc}0&1\\1&0\end{array}\right]

- Because the x-coordinate and y-coordinate change places.

* Now lets solve the problem

- We will multiply the matrix of the reflection about y = x

 by each point to find the image of each point

- The dimension of the matrix of the reflection about y = x

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 then the dimension of the matrix of each image is 2×1

∵ The point R is (-2 , 5)

∴ R'=\left[\begin{array}{cc}0&1\\1&0\end{array}\right]\left[\begin{array}{cc}-2\\5\end{array}\right]=

  \left[\begin{array}{c}(0)(-2)+(1)(5)\\(1)(-2)+(0)(5)\end{array}\right]=\left[\begin{array}{c}5\\-2\end{array}\right]

∴ R' is (5 , -2)

∵ The point S is (5 , 3)

∴ S'=\left[\begin{array}{cc}0&1\\1&0\end{array}\right]\left[\begin{array}{c}5\\3\end{array}\right]=

  \left[\begin{array}{c}(0)(5)+(1)(3)\\(1)(5)+(0)(3)\end{array}\right]=\left[\begin{array}{c}3\\5\end{array}\right]

∴ S' is (3 , 5)

∵ The point T is (6 , -7)

∴ T'=\left[\begin{array}{cc}0&1\\1&0\end{array}\right]\left[\begin{array}{c}6\\-7\end{array}\right]=

  \left[\begin{array}{c}(0)(6)+(1)(-7)\\(1)(6)+(0)(-7)\end{array}\right]=\left[\begin{array}{c}-7\\6\end{array}\right]

∴ T' is (-7 , 6)

* Lets look to the figures to find the right answer

∵ The R' is (5 , -2) , S' is (3 , 5) , T' is (-7 , 6)

∴ The right answer is (d)

4 0
4 years ago
Hey can you please help me posted picture of question
aleksandr82 [10.1K]

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aleksandr82 [10.1K]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
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