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Alexus [3.1K]
2 years ago
11

Can u solve 7-12 and 14 please

Mathematics
1 answer:
AlexFokin [52]2 years ago
4 0

Answer:

1. 19

Step-by-step explanation:

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\bf 2sin^2(2x)=2\implies sin^2(2x)=\cfrac{2}{2}&#10;\\\\\\&#10;sin^2(2x)=1\implies [sin(2x)]^2=1\implies sin(2x)=\pm\sqrt{1}&#10;\\\\\\&#10;sin(2x)=\pm 1\implies sin^{-1}[sin(2x)]=sin^{-1}(\pm 1)

\bf \measuredangle 2x=sin^{-1}(\pm 1)\implies \measuredangle 2x=&#10;\begin{cases}&#10;\frac{\pi }{2}\\\\&#10;\frac{3\pi }{2}&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;\measuredangle 2x=\cfrac{\pi }{2}\implies \measuredangle x=\cfrac{\pi }{4}\qquad \qquad \qquad \qquad \measuredangle 2x=\cfrac{3\pi }{2}\implies \measuredangle x=\cfrac{3\pi }{4}
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