Speed = Distance / Time
Distance = 5t^4 - 10t^2+6
Time = t+2
Now:
5t^4 - 10t^2 + 6 | t+2
-5t^4 -10t^3 5t^3 - 10t^2 + 10t - 20
\\\\\ -10t^3-10t^2+6
+10t^3+20t^2
\\\\\\\ 10t^2+6
-10t^2-20t
\\\\\ -20t+6
+20t+40
\\\\\ 46
<span>C. 5t^3-10t^2+10t-20+(46)/(t+2))</span>
Answer:
395149.22 cubic inches.
Step-by-step explanation:
The volume of a tank with length (L), width (W) and height (H) is given by
V = LWH ........ (1)
Now, the interior dimensions of a tank are 82.5 inches long, 58.5 inches wide, and 81.875 inches tall.
So, L = 82.5 inches, W = 58.5 inches and H = 81.875 inches.
Therefore, V = (82.5 × 58.5 × 81.875) = 395149.22 cubic inches.
Hence, the approximate volume of the tank is 395149.22 cubic inches. (Answer)
Hello!
I was looking for this answer as well, but I took the quiz and got it correct. The answer is 5 units.
good luck!
