Answer:
A = 26
Step-by-step explanation:
sum of students = classA + classB + classC
let's say classA = A, classB = B, and classC = C
A + B + C = 66
class A has five more students than class B, so A = 5 more than B so A = 5+B
class C has 2 less students than class B, so C = 2 less than class B = B -2, so C = B-2
A + B + C = 66
A = 5+B
C = B-2
substitute 5+B for A and B-2 for C in the first equation to limit this to one variable (B)
(5+B) + B + (B-2) = 66
3B + 3 = 66
subtract 3 from both sides to isolate the variable and its coefficient
3B = 63
divide both sides by 3 to solve for B
B = 21
A = 5 + B = 5 + 21 = 26
Check the attachment below. Answer: 5/2
♥It says that he adds 12$ each week, and by the end of 3 weeks he had 60. Well if you do 12*3
And that =36.
But as you can see its not 60 so we have to find out how much money he had in there before.
He had 24$ in there before he started doing this.
You can find this by doing 36+x=60 and 36+24=60.
Now if you do 12*15
You get 180.
Now add the 24 dollars he already had in there.
180+24=204
He had 204$ at the end of wk.15
♥Hope this helps!♥
Let's solve your equation step-by-step.
25m+100−24m−75=68
Step 1: Simplify both sides of the equation.
25m+100−24m−75=68
25m+100+−24m+−75=68
(25m+−24m)+(100+−75)=68(Combine Like Terms)
m+25=68
m+25=68
Step 2: Subtract 25 from both sides.
m+25−25=68−25
m=43
Answer:
m=43
A is correct.
-8, -4, 0, 2
-|-4| becomes -(4) which becomes -4.
