3 years ago

H=-16t^2+v0t+h0 feet

1 answer:

8 0

<span> <span>THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet</span></span>

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