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nikitadnepr [17]
4 years ago
9

H=-16t^2+v0t+h0 feet

Mathematics
1 answer:
Liula [17]4 years ago
8 0
<span> <span>THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet</span></span>
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Find the value of KL.<br> KL= 3x + 2 and LM= 5x - 10
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From the given graph, we can tell kl=lm 

therefore,

3x + 2 = 5x - 10

3x+2-2=5x-10-2 

subtract 2 from both sides. 

3x+ 0 =5x-12 3x=5x-12 

3x-5x=5x-5x-12 

subtract 5x from both sides.

-2x=0-12 -2x=-12 (-2x)/-2=-12/-2 

divide both sides by -2. 

1x= 6 -12/-2=6 

and of course the -2 and -2 cancel on left side leaving 1x. 

x=6

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