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2 years ago

Multiplying fractions. Eight ninths times four fifths

Mathematics

1 answer:

Leni [432]2 years ago

6 0

$\frac{8}{9} *\frac{4}{5} = \frac{8*4}{9*5}= \\\frac{32}{45}$ \frac{32}{45} [/tex]

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Suppose the function y = 30,000(1.06)x models the annual profit for a small business x years after 2000. Find the profit at the

goldfiish [28.3K]

From 2000 to 2011, there are 11 years. From the given function, we can calculate the profit for a small business at the end of 2011 by substituting 11 to the x of the given equation.
y = (30,000)(1.06)(11)
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Thus, the profit at the end of 2011 is approximately $349,800.

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3 years ago

Shane has a segment with endpoints C(3, 4) and D(11, 3) that is divided by a point E such that CE and DE form a 3:5 ratio. He kn

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B=5/3 is the answer.........

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3 years ago

Which is the equation of a hyperbola centered at the origin with x-intercept +\- 3 and asymptote y=2x

Radda [10]

Answer:

${\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}$

Step-by-step explanation:

The hyperbola has x-intercepts, so it has a horizontal transverse axis.

The standard form of the equation of a hyperbola with a horizontal transverse axis is $\dfrac{(x - h)^{2}}{a^{2}} - \dfrac{(y - k)^{2}}{b^{2}} = 1$

The center is at (h,k).

The distance between the vertices is 2a.

The equations of the asymptotes are $y = k \pm \dfrac{b}{a}(x - h)$

1. Calculate h and k. The hyperbola is symmetric about the origin, so

h = 0 and k = 0

2. For 'a': 2a = x₂ - x₁ = 3 - (-3) = 3 + 3 = 6

a = 6/2 = 3

3. For 'b': The equation for the asymptote with the positive slope is

$y = k + \dfrac{b}{a}(x - h) = \dfrac{b}{a}x$

Thus, asymptote has the slope of

$\begin{array}{rcl}m& =& \dfrac{b}{a}\\\\2& =& \dfrac{b}{3}\\\\b& =& \mathbf{6}\end{array}$

4. The equation of the hyperbola is

$\large \boxed{\mathbf{\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}}$

The attachment below represents your hyperbola with x-intercepts at ±3 and asymptotes with slope ±2.

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2 years ago

You build a fence around garden that measures 10 x 15 feet; how many feet of chain link fence will you need?

Neporo4naja [7]

Answer:

50 feet

Step-by-step explanation:

We have to find the perimeter of the fence surrounding the garden.

2l+2w

2(15) + 2(10)

30 + 20

= 50

50 feet will be needed.

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3 years ago

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boyakko [2]

Answer:

Moose attacks spike in September and October which is mating season, and early Spring also due to young calves being raised. Many moose attacks on humans are actually provoked from dogs. Moose hate dogs and wolves, and become extremely aggressive by their presence, especially at a dog that barks.

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2 years ago

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