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loris [4]
4 years ago
14

What is the value of x?

Mathematics
2 answers:
KonstantinChe [14]4 years ago
7 0
Sine rule = c/SinC = b/SinB = a/SinA

SO 13/Sin40 = x/Sin87
20.224409... = x/Sin87
x = 20.19669...

So rounded to the nearest tenth,
x = 20.2
zhenek [66]4 years ago
6 0

I took the K12 test

The answer is 16.3 cm


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Quadrilateral ABCD has vertices A (-3, 0), B (2, 4), C (3, 1), and D (-4, -3). Calculate the perimeter of the quadrilateral. Rou
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Answer:

Perimeter of the Quadrilateral=20.78

Step-by-step explanation:

Perimeter of the Quadrilateral= AB+BC+CD+AD

Finding the sides of the quadrilateral using the Distance formula:

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AB=\sqrt{(2-(-3))^2+(4-0)^2}\\\\ =\sqrt{(2+3)^2+4^2}\\\\ =\sqrt{5^2+4^2} \\\\=\sqrt{25+16}\\\\ =\sqrt{41}\\

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BC=

         \sqrt{(3-2)^2+(1-4)^2} \\\\=\sqrt{1^2+(-3)^2} \\\\=\sqrt{1+9}\\\\ =\sqrt{10}

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      CD=\sqrt{(-4-3)^2+(-3-1)^2} \\\\=\sqrt{(-7)^2+(-4)^2} \\\\=\sqrt{49+16}\\\\=\sqrt{65}\\\\ =8.06

AD=\sqrt{(-4-(-3))^2+(-3-0)^2} \\\\=\sqrt{(-4+3)^2+(-3)^2} \\\\=\sqrt{(-1)^2+(-3)^2} \\\\=\sqrt{1+9}\\\\=\sqrt{10} \\\\ =3.16

Perimeter of the quadrilateral= AB+BC+CD+AD

             =6.40+3.16+8.06+3.16

              =20.78

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Step-by-step explanation:

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