It wants it to be in slope-intercept form.
y=mx+b
We have to first find the slope and plug it into point-slope form.
y-y1=m(x-x1)
Find the slope of the second line. (I did this one first on accident)
Rise/run= 3/1= 3 The slope is 3. Plug that in along with the point (0,3)
y-3=3(x-0)
y-3=3x
Add 3 to the other side.
y= 3x +3 <- <em>for the second line</em><em>
</em>
Now, the second.
rise/run= 1/2= .5 Use point (6,0)
y-0=.5(x-6)
y= .5x-3
y=.5x-3 <- for the first line
I hope this helps!
~kaiker
The answer is 4/27p9q3 Hope I helped!
Answer:
B)-4
Step-by-step explanation:
y=mx+c
sub in a point and gradient/slope to get c
-7=3(-1)+c
-7=-3+c
-7+3=c
c=-4
y=3x-4
if u looking for the y intercept make x=0
y=3(0)-4
y=-4
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