Ok let us see it this way:
If x is the measure of the angle we require
<span>The complement is 90 - x </span>
<span>one half of the complement is therefore 0.5(90 - x)
</span><span>18 degrees less than one half of the measure of the complement is
0.5(90 - x) -18
</span>I hope this can be of good use
<h3>
Answer: H = {3, 5, 7}</h3>
Explanation:
We simply list any odd number that is between 2 and 8. The term "roster form" can be thought of as listing the roster of a sports team (eg: baseball). So instead of describing what the numbers look like, we list out the numbers themselves. Those numbers being 3, 5 and 7.
Something like {2,4,6,8} is ruled out because we're dealing with odd numbers only.
Explanation:
The given equation is False, so cannot be proven to be true.
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Perhaps you want to prove ...
![2\tan{x}=\dfrac{\cos{x}}{\csc{(x)}-1}+\dfrac{\cos{x}}{\csc{(x)}+1}](https://tex.z-dn.net/?f=2%5Ctan%7Bx%7D%3D%5Cdfrac%7B%5Ccos%7Bx%7D%7D%7B%5Ccsc%7B%28x%29%7D-1%7D%2B%5Cdfrac%7B%5Ccos%7Bx%7D%7D%7B%5Ccsc%7B%28x%29%7D%2B1%7D)
This is one way to show it:
![2\tan{x}=\cos{(x)}\dfrac{(\csc{(x)}+1)+(\csc{(x)}-1)}{(\csc{(x)}-1)(\csc{(x)}+1)}\\\\=\cos{(x)}\dfrac{2\csc{(x)}}{\csc{(x)}^2-1}=2\cos{(x)}\dfrac{\csc{x}}{\cot{(x)}^2}=2\dfrac{\cos{(x)}\sin{(x)}^2}{\cos{(x)}^2\sin{(x)}}\\\\=2\dfrac{\sin{x}}{\cos{x}}\\\\2\tan{x}=2\tan{x}\qquad\text{QED}](https://tex.z-dn.net/?f=2%5Ctan%7Bx%7D%3D%5Ccos%7B%28x%29%7D%5Cdfrac%7B%28%5Ccsc%7B%28x%29%7D%2B1%29%2B%28%5Ccsc%7B%28x%29%7D-1%29%7D%7B%28%5Ccsc%7B%28x%29%7D-1%29%28%5Ccsc%7B%28x%29%7D%2B1%29%7D%5C%5C%5C%5C%3D%5Ccos%7B%28x%29%7D%5Cdfrac%7B2%5Ccsc%7B%28x%29%7D%7D%7B%5Ccsc%7B%28x%29%7D%5E2-1%7D%3D2%5Ccos%7B%28x%29%7D%5Cdfrac%7B%5Ccsc%7Bx%7D%7D%7B%5Ccot%7B%28x%29%7D%5E2%7D%3D2%5Cdfrac%7B%5Ccos%7B%28x%29%7D%5Csin%7B%28x%29%7D%5E2%7D%7B%5Ccos%7B%28x%29%7D%5E2%5Csin%7B%28x%29%7D%7D%5C%5C%5C%5C%3D2%5Cdfrac%7B%5Csin%7Bx%7D%7D%7B%5Ccos%7Bx%7D%7D%5C%5C%5C%5C2%5Ctan%7Bx%7D%3D2%5Ctan%7Bx%7D%5Cqquad%5Ctext%7BQED%7D)
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We have used the identities ...
csc = 1/sin
cot = cos/sin
csc^2 -1 = cot^2
tan = sin/cos
Answer:The expression can be simplified in following steps;
Step-by-step explanation:
(16+a)+15=0
16+15+a=0
31+a=0
a=-31
To find the absolute value of a negative number, you can simply remove the negative. ., -235 turns into 235, and 235 is greater than 220.