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oksian1 [2.3K]
4 years ago
8

Help me plzzzzzz!!!!

Mathematics
2 answers:
marissa [1.9K]4 years ago
8 0
5^-3 = 1/125
-5^-3 = -1/125
(-5^-3)^-1 = -125
(-5^-3)^0 = 1
stepan [7]4 years ago
3 0

5⁻³ = \frac{1}{5^{3} } = \frac{1}{5*5*5} = \frac{1}{125}

-5⁻³ = -(\frac{1}{5^{3} }) = -(\frac{1}{5*5*5}) = \frac{-1}{125}

(-5⁻³)⁻¹ = \frac{1}{-5^{-3} } = -(5³) = -(5*5*5) = -125

(-5⁻³)⁰ = 1 (anything to the zero power equals 1,   <em>except 0⁰ = 0</em>)


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Answer:

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Step-by-step explanation:

To find the width, follow these steps.

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To find the area, multiply the width and the length together.

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