Answer:
18 combinations
Step-by-step explanation:
There are three chocolates and six different options to mix with those chocolates. Each chocolate has six different options. So, it comes to 6 + 6 + 6 or 6 • 3 whoch equals 18 different combinations.
(m+4)(m+1)
=m^2+5m+4........
31. There are C(5, 2) = 10 ways to choose 2 colors from a group of 10 colors if you don't care about the order. (Here, we treat blue background with violet letters as being indistinguishable from violet background with blue letters.)
Only one of those 10 pairs is "B and V", so the probability is 1/10.
a) P(B and V) = 10%
32. The 12 inch dimension on the figure is 0 inches for the cross section. The remaining dimensions of the cross section are
c) 5 in. × 4 in.
_____
C(n, k) = n!/(k!·(n-k)!)
C(5, 2) = 5!/(2!·3!) = 5·4/(2·1) = 10
B and C are correct because you do basic PEMDAS and get 58 for both those expressions. If this is right could you possibly give me brainliest? Hope this helped.
