Question

Suppose that the uncertainty in determining the position of an electron circling an atom in an orbit is 0.4 A. What is the uncertainty in its velocity

Answer 1

Answer:

Explanation:

Applying the Heisenberg uncertainty principle,

Δx X mΔv = h/4π

where Δx = uncertainty in measurement of position

Δv = uncertainty in measurement of velocity

m = mass of object

h = planck's constant

Here:

Δv = 0.4 A° = 4.0 x 10^-11 m

mass, m = 9.11 x 10^-31 Kg

Plugging the values,

4.0 x 10^-11 x Δ v = (6.626 x 10^-34) / (4 x 3.14 x 9.11E-31)

4.0 x 10^-11 x Δ v = 5.791 x 10^-5

Δv = 1.448 x 10^6 m/s, the uncertainty in its velocity

Answer = 1.45 x 10^6 m/s